python - 与 Python 中的字典比较

Question

我有一个函数，它接受一个字符串，它计算单个字符并将字符连同它显示的时间量一起放入一个字符串中。例如：

isanagram("surfer")

返回

w1 = {'a': 0, 'b': 0, 'c': 0, 'd': 0, 'e': 1, 'f': 1, 'g': 0, 'h': 0, 'i': 0, 'j': 0, 'k': 0, 'l': 0, 'm': 0, 'n': 0, 'o': 0, 'p': 0, 'q': 0, 'r': 2, 's': 1, 't': 0, 'u': 1, 'v': 0, 'w': 0, 'x': 0, 'y': 0, 'z': 0}

尽管当我将此函数与两个不同的参数进行比较时，打印语句输出True而不是False，这显然应该是。有没有人可以看看。这是我的代码：

alphabetlist = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
    alphabetdict = {}
    newalphadict = {}    
              
    def isanagram(aword):
        for i in alphabetlist:
            count = word.count(i) 
            alphabetdict[i] = count
            
        return alphabetdict
    
     print(isanagram("computer") == isanagram("science")) #outputting True. Should be outputting False.

标签： pythonpython-3.xfunctiondictionary

Answer 1

alphabetlist = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
        
def isanagram(word=''):
    alphabetdict = {}
    for i in alphabetlist:
        count = word.count(i) 
        alphabetdict[i] = count
    
    return alphabetdict

print(isanagram("computer") == isanagram("science")) #-> False