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rust - 如何将 16 字节的内存加载到 Rust __m128i 中？

问题描述

我正在尝试将 16 字节的内存加载到模块中的__m128i类型中std::arch：

#[cfg(all(target_arch = "x86_64", target_feature = "sse2"))]
use std::arch::x86_64::__m128i;

fn foo() {
    #[cfg(all(target_arch = "x86_64", target_feature = "sse2"))]
    use std::arch::x86_64::_mm_load_si128;

    unsafe {
        let mut f: [i8; 16] = [0; 16];
        f[0] = 5;
        f[1] = 66;
        let g = _mm_load_si128(f as *const __m128i);
    }
}

fn main() {
    foo();
}

我的代码导致错误：

error[E0605]: non-primitive cast: `[i8; 16]` as `*const __m128i`
  --> src/main.rs:12:32
   |
12 |         let g = _mm_load_si128(f as *const __m128i);
   |                                ^^^^^^^^^^^^^^^^^^^ an `as` expression can only be used to convert between primitive types or to coerce to a specific trait object

从文档中不清楚如何使用_mm_load_si128从现有内存或现有类型加载字节。我希望能够__m128i 通过加载内在函数从某些现有类型中加载字节。

标签： rustssesimdintrinsics

解决方案

通过负载内在

内在函数是文档中列出的函数。模块中的示例涵盖了您从内存加载的具体示例：

let invec = _mm_loadu_si128(src.as_ptr() as *const _);

对于您的情况：

let g = _mm_load_si128(f.as_ptr() as *const _);

也可以看看：

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