首页 > 解决方案 > 错误:函数“rl_replace_line”的隐式声明在 C99 中无效 [-Werror,-Wimplicit-function-declaration]

问题描述

我试图在我的代码中实现 rl_replace_line() 但是当我尝试像这样编译它时:

gcc -lreadline test.c -o test

我收到此错误消息:

error: implicit declaration of function 'rl_replace_line' is invalid in C99 [-Werror,-Wimplicit-function-declaration]

但是我认为我使用了好的头文件?这是我的代码:

# include <stdio.h>
# include <readline/readline.h>
# include <readline/history.h>
# include <unistd.h>
# include <stdlib.h>

char    *get_line()
{
    char *line;

    line = NULL;
    if (line)
    {
        free(line);
        line = NULL;
    }
    line = readline("Minishell>");
    if (line)
        add_history(line);
    return (line);
}

void    sig_handler(int signum)
{
    if (signum == SIGINT)
    {
        printf("\n");
        rl_on_new_line();
        rl_replace_line("", 0);
        rl_redisplay();
    }
}

int main(void)
{
    char    *line;

    signal(SIGINT, sig_handler);
    line = get_line();
    printf("%s\n", line);
}

我不明白为什么它不起作用,我希望你们能帮助谢谢!

标签: cgcccompiler-errorsreadline

解决方案


我设法通过包含正确的路径来解决我的问题:

-L .brew/opt/readline/lib-I .brew/opt/readline/include

现在我像这样编译并且它正在工作:

gcc test.c -o test -lreadline -L .brew/opt/readline/lib -I .brew/opt/readline/include

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