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python - Spotify discord.py api 的 if & else 有问题

问题描述

对于代码的最后一点elif isinstance(activity == None, Spotify)&await ctx.send(f'{user.name} is not listening to anything :shrug:')运行时没有错误代码，但是如果我的 spotify 没有播放它在我输入命令时不会打印它

完整代码如下：

@commands.command()
    async def spot(self, ctx, user: discord.Member = None):
        if user == None:
            user = ctx.author
            pass
        if user.activities:
            for activity in user.activities:
                if isinstance(activity, Spotify):

                    embed = discord.Embed(
                        title=f"{user.name}'s Spotify",
                        description="Currently listening to {}".format(activity.title),
                        color=user.color)

                    embed.set_thumbnail(url=activity.album_cover_url)
                    embed.add_field(name="Artist", 
                                    value=activity.artist,
                                    inline=False)
                    embed.add_field(name="Album", 
                                    value=activity.album,
                                    inline=False)
                    
                    m1, s1 = divmod(int(activity.duration.seconds), 60)
                    song_length = f'{m1}:{s1}'
                    embed.add_field(name="Song Duration",
                                    value=song_length,
                                    inline=True)                   
                    embed.add_field(name="Track Link", 
                                    value=f"[{activity.title}](https://open.spotify.com/track/{activity.track_id})",
                                    inline=True)

                    embed.set_footer(text=f'Requested by : {ctx.author}',
                                    icon_url=ctx.author.avatar_url)
                    await ctx.send(embed=embed)

                elif isinstance(activity == None, Spotify):
                    await ctx.send(f'{user.name} is not listening to anything :shrug:')

标签： pythondiscorddiscord.pyspotify

解决方案

我复制了您的代码并为自己尝试了。更改线路elif isinstance(activity == None, Spotify):为else:我修复它。

但是我注意到您的代码中有一个错误，它会检查用户的每个活动，并且对于每个活动都会发送一条消息。因此，当您收听 Spotify 时，它会说您正在收听而不是同时收听。因此，我重新编写了您的代码，因此它首先检查是否存在 Spotify 活动，然后根据该活动发送消息。

这是重新编写的代码：

@commands.command()
  async def spot(self, ctx, user: discord.Member=None):
    user = user if user else ctx.author

    activity = None

    for act in user.activities:
      if isinstance(act, Spotify):
        activity = act
        break
      
    if activity:
      embed = discord.Embed(
        title=f"{user.name}'s Spotify",
        description="Currently listening to {}".format(activity.title),
        color=user.color
      )

      embed.set_thumbnail(url=activity.album_cover_url)

      embed.add_field(
        name="Artist", 
        value=activity.artist,
        inline=False
      )

      embed.add_field(
        name="Album", 
        value=activity.album,
        inline=False
      )
      
      m1, s1 = divmod(int(activity.duration.seconds), 60)

      song_length = f'{m1}:{s1}'

      embed.add_field(
        name="Song Duration",
        value=song_length,
        inline=True
      )                   
      embed.add_field(
        name="Track Link", 
        value=f"[{activity.title}](https://open.spotify.com/track/{activity.track_id})",
        inline=True
      )

      embed.set_footer(text=f'Requested by : {ctx.author}', icon_url=ctx.author.avatar_url)
      
      await ctx.send(embed=embed)

    else:
      await ctx.send(f'{user.name} is not listening to anything :shrug:')

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