sed - Extract text between matched pattern and append text before the result

Question

I have a line of code like this "some_random_text_AP3_somerandomtext".

I'm trying to extract only this AP3. Since AP is fixed all the time, I used below solution.

echo "some_random_text_AP3_somerandomtext" | sed -n 's/.*AP\(.*\)_.*/\1/p'

It is successfully returning the number which is just 3, so I used the below solution to append AP to it.

echo "some_random_text_AP3_somerandomtext" | sed -n 's/.*AP\(.*\)_.*/\1AP/p'

It is appending after 3 and the result is 3AP, I actually want to append this before 3 like AP3, but not 3AP.

Could someone point me out how to append it before?

标签： sed

Answer 1

^{根据要求将评论转移到答案中。}

替换's/.*AP\(.*\)_.*/\1AP/p'放在AP匹配的内容之后 ( \1)。你大概需要's/.*AP\(.*\)_.*/AP\1/p'.

此外，.*应该[^_]*防止贪婪影响您的结果（AP3例如，如果后面的随机文本包含下划线）。因此，为了安全起见，您可能应该使用：

sed -n 's/.*AP\([^_]*\)_.*/AP\1/p'