r - R中按因子着色的线配对箱线图
问题描述
我从以下数据制作了一个配对箱线图:
manage natcode sites variable value
F Y MF1 PESUKmedian 59.4363000
F Y MF2 PESUKmedian 2.9628212
F Y MF3 PESUKmedian 11.9980950
F Y MF4 annualmedian 5.5549982
M Y MM1 annualmedian 10.9977350
M Y MM2 PESUKmedian 19.0449542
使用代码:
ggplot(df2, aes(variable, value)) +
geom_boxplot(width=0.3, size=1.5, fatten=1.5, colour="black") +
geom_point(colour="red", size=2, alpha=0.5) +
geom_line(aes(group=sites), colour= "black") +
theme_classic()
这是可以接受的,但我想找出为什么有些变化比其他变化更大,如果我可以通过“管理”或“natcode”为 geom_line 中的线条着色会很棒,但我似乎无法弄清楚这一点
解决方案
或者,如果您想通过 natcode 着色,只需将行更改geom_line(aes(group = sites, color = manage))
为geom_line(aes(group = sites, color = natcode))
library(ggplot2)
df2 <- data.frame(manage = c("F","F","F","F","M","M"),
natcode = c("Y","Y","Y","Y","Y","Y"),
sites = c("MF1","MF2","MF3","MF4","MF1","MF2"),
variable = c("PESUKmedian","PESUKmedian","PESUKmedian","annualmedian","annualmedian","PESUKmedian"),
value = c(59.4363000,2.9628212,11.9980950,5.5549982,10.9977350,19.0449542))
df2
manage natcode sites variable value
F Y MF1 PESUKmedian 59.436300
F Y MF2 PESUKmedian 2.962821
F Y MF3 PESUKmedian 11.998095
F Y MF4 annualmedian 5.554998
M Y MF1 annualmedian 10.997735
M Y MF2 PESUKmedian 19.044954
ggplot(df2, aes(variable, value)) +
geom_boxplot(width=0.3, size=1.5, fatten=1.5, colour="black") +
geom_point(colour="red", size=2, alpha=0.5) +
geom_line(aes(group=sites, color = manage)) +
theme_classic()
推荐阅读
- python - PyQt5 项目结构和 PyInstaller ModuleNotFoundError
- https - MINIFI CPP 无法调用 HTTPS
- ios - Objective-c App 在 iOS 13 中崩溃(搜索栏问题)
- python-3.x - 调用帮助函数有什么问题?
- angular - @ngrx/entity `Cannot read property 'ids' of undefined` 与 @ngrx/store 一起使用时?在定义适配器时已经考虑了自定义 ID
- reactjs - 如何将多个复选框添加到一个状态
- c# - 如何在 Linq 语句中获取多个链接子项的父/源项?
- java - Android无法在内部存储上创建目录
- scala - Array((1L, 2L)) 是做什么的?
- google-text-to-speech - Google text-to-speech (Wavenet) 是否有每种支持语言的日期格式列表?