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python - 1. 打印飞利浦发送的所有货物详情？2.打印所有处于“在途”状态的货物

问题描述

这是给定的字典

dict1= {101: {'Sender': 'Phillip', 'Receiver': 'Ramya', 'Start date': '14-03-2020', 'Delivery date': '25-03-2020', 'Sender location': 'Area 1', 'Receiver location': 'Area 6', 'Delivery status': 'Delivered', 'Shipping cost': 198}, 102: {'Sender': 'Romesh', 'Receiver': 'Phillip', 'Start date': '18-06-2020', 'Delivery date': '09-07-2020', 'Sender location': 'Area 2', 'Receiver location': 'Area 4', 'Delivery status': 'Delivered', 'Shipping cost': 275}, 103: {'Sender': 'Omega lll', 'Receiver': 'Ramya', 'Start date': '01-12-2020', 'Delivery date': 'Null', 'Sender location': 'Area 5', 'Receiver location': 'Area 1', 'Delivery status': 'In Transit', 'Shipping cost': 200}, 104: {'Sender': 'Phillip', 'Receiver': 'John', 'Start date': '23-06-2020', 'Delivery date': '25-06-2020', 'Sender location': 'Area 1', 'Receiver location': 'Area 4', 'Delivery status': 'Delivered', 'Shipping cost': 314}, 105: {'Sender': 'Ramya', 'Receiver': 'Romesh', 'Start date': '29-08-2020', 'Delivery date': '10-09-2020', 'Sender location': 'Area 5', 'Receiver location': 'Area 3', 'Delivery status': 'Delivered', 'Shipping cost': 275}, 106: {'Sender': 'John', 'Receiver': 'Omega lll', 'Start date': '28-06-2020', 'Delivery date': 'Null', 'Sender location': 'Area 3', 'Receiver location': 'Area 1', 'Delivery status': 'In Transit', 'Shipping cost': 270}}

有人可以帮我解决这个问题吗

标签： pythonpython-3.xdictionary

解决方案

让我们只选择 Sender 是 Phillip 的字典值。

# dict1.values() gives an array of the values of dict1
# filter takes a function that determines which values to keep (lambda) and the dict1.values() array
#    in this case it only accepts values with 'Sender' == 'Phillip'
# list converts filter's output into a normal list
dict1 = {101: {'Sender': 'Phillip', 'Receiver': 'Ramya', 'Start date': '14-03-2020', 'Delivery date': '25-03-2020', 'Sender location': 'Area 1', 'Receiver location': 'Area 6', 'Delivery status': 'Delivered', 'Shipping cost': 198}, 102: {'Sender': 'Romesh', 'Receiver': 'Phillip', 'Start date': '18-06-2020', 'Delivery date': '09-07-2020', 'Sender location': 'Area 2', 'Receiver location': 'Area 4', 'Delivery status': 'Delivered', 'Shipping cost': 275}, 103: {'Sender': 'Omega lll', 'Receiver': 'Ramya', 'Start date': '01-12-2020', 'Delivery date': 'Null', 'Sender location': 'Area 5', 'Receiver location': 'Area 1', 'Delivery status': 'In Transit', 'Shipping cost': 200}, 104: {'Sender': 'Phillip', 'Receiver': 'John', 'Start date': '23-06-2020', 'Delivery date': '25-06-2020', 'Sender location': 'Area 1', 'Receiver location': 'Area 4', 'Delivery status': 'Delivered', 'Shipping cost': 314}, 105: {'Sender': 'Ramya', 'Receiver': 'Romesh', 'Start date': '29-08-2020', 'Delivery date': '10-09-2020', 'Sender location': 'Area 5', 'Receiver location': 'Area 3', 'Delivery status': 'Delivered', 'Shipping cost': 275}, 106: {'Sender': 'John', 'Receiver': 'Omega lll', 'Start date': '28-06-2020', 'Delivery date': 'Null', 'Sender location': 'Area 3', 'Receiver location': 'Area 1', 'Delivery status': 'In Transit', 'Shipping cost': 270}}
phillips = list(filter(lambda value: value['Sender'] == 'Phillip',
                       dict1.values()))
print(phillips)

结果是

[{'Sender': 'Phillip', 'Receiver': 'Ramya', 'Start date': '14-03-2020', 'Delivery date': '25-03-2020', 'Sender location': 'Area 1', 'Receiver location': 'Area 6', 'Delivery status': 'Delivered', 'Shipping cost': 198}, {'Sender': 'Phillip', 'Receiver': 'John', 'Start date': '23-06-2020', 'Delivery date': '25-06-2020', 'Sender location': 'Area 1', 'Receiver location': 'Area 4', 'Delivery status': 'Delivered', 'Shipping cost': 314}]

您可以使用完全相同的策略filter(lambda x: _____, dict1.values())来查找在途的物品。

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