首页 > 解决方案 > 使用 chrono 处理 rust 中的 unix 时间戳

问题描述

我似乎无法弄清楚如何使用chrono.

我有以下代码,但是naivevarsdatetime不正确:

use chrono::{Utc, DateTime, NaiveDateTime};

fn main() {
    println!("Hello, world!");

    let timestamp = "1627127393230".parse::<i64>().unwrap();
    let naive = NaiveDateTime::from_timestamp(timestamp, 0);
    let datetime: DateTime<Utc> = DateTime::from_utc(naive, Utc);

    println!("timestamp: {}", timestamp);
    println!("naive: {}", naive);
    println!("datetime: {}", datetime);
}

输出:

❯ cargo r
    Finished dev [unoptimized + debuginfo] target(s) in 0.01s
     Running `target/debug/utc`
Hello, world!
timestamp: 1627127393230
naive: +53531-08-13 23:27:10
datetime: +53531-08-13 23:27:10 UTC

当正确的日期时间1627127393230是:

GMT: Saturday, July 24, 2021 11:49:53.230 AM

有人可以告诉我我在这里缺少什么。谢谢

编辑:

最终解决方案:

use chrono::{DateTime, Utc, NaiveDateTime};

pub fn convert(timestamp: i64)  -> DateTime<Utc> {
    let naive = NaiveDateTime::from_timestamp_opt(timestamp / 1000, (timestamp % 1000) as u32 * 1_000_000).unwrap();
    DateTime::<Utc>::from_utc(naive, Utc)
}


#[test]
fn test_timestamp() {
    let timestamp = 1627127393230;
    let ts = convert(timestamp);
    assert_eq!(ts.to_string(), "2021-07-24 11:49:53.230 UTC")
}

标签: rustchrono

解决方案


from_timestamp 不支持毫秒。您可以将毫秒放在第二个参数中作为纳秒。但是你必须把它从时间戳中取出。

查看 substring crate 或这样做:

use chrono::{DateTime, NaiveDateTime, Utc}; 

fn main() {
    let timestamp = 1627127393i64;
    let nanoseconds = 230 * 1000000;
    let datetime = DateTime::<Utc>::from_utc(NaiveDateTime::from_timestamp(timestamp, nanoseconds), Utc);
    println!("{}", datetime);
}

使用子字符串箱:

use substring::Substring;
use chrono::{DateTime, NaiveDateTime, Utc}; 

fn main() {
    let timestamp = "1627127393230";
    let nanoseconds = substring(timestamp, 11, 3).parse::<i64>().unwrap() * 1000000;
    let timestamp = substring(timestamp, 1, 10).parse::<i64>().unwrap();
    let datetime = DateTime::<Utc>::from_utc(NaiveDateTime::from_timestamp(timestamp, nanoseconds), Utc);
    println!("{}", datetime);
}

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