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python - 如何使用包含斜杠字符“/”的密码的电子邮件 URL

问题描述

对于 Django 应用程序，我正在尝试将环境变量设置EMAIL_URL为包含.smtp://username:password@email-smtp.us-east-1.amazonaws.com:587/?tls=Truepassword/

/由于某种原因，Amazon SES 给了我一个包含字符的密码。

例如：

export EMAIL_URL="smtp://AKIAYZT73XCKGD:BFB6UvkMgn9dniEGQZc/xM/KDS9Agc/S2@email-smtp.us-east-2.amazonaws.com:587/?tls=True"

然后运行：

python3.9 manage.py runserver

但我收到一个错误：

ValueError：端口无法转换为整数值，如“BFB6UvkMgn9dniEGQZc”

在这个文件中抛出错误：

myapp-venv/lib/python3.9/site-packages/dj_email_url.py

在'EMAIL_PORT': url.port,这个函数的声明中：

def parse(url):
    """Parses an email URL."""

    conf = {}

    url = urllib.parse.urlparse(url)
    qs = urllib.parse.parse_qs(url.query)

    # Remove query strings
    path = url.path[1:]
    path = path.split('?', 2)[0]

    # Update with environment configuration
    conf.update({
        'EMAIL_FILE_PATH': path,
        'EMAIL_HOST_USER': unquote(url.username),
        'EMAIL_HOST_PASSWORD': unquote(url.password),
        'EMAIL_HOST': url.hostname,
        'EMAIL_PORT': url.port,
        'EMAIL_USE_SSL': False,
        'EMAIL_USE_TLS': False,
    })

    if url.scheme in SCHEMES:
        conf['EMAIL_BACKEND'] = SCHEMES[url.scheme]

    # ...

    return conf

试过了

我试图逃避/with\但它没有用！

试过了

正如@bdbd 所建议的，尝试使用以下语句：

EMAIL_URL = urllib.parse.quote(EMAIL_URL)

就在调用之前dj_email_url.parse：

email_config = dj_email_url.parse(EMAIL_URL)

但问题是，在这种情况下，结果email_config将没有EMAIL_BACKEND. 我的意思是，这个陈述不能被评估：

EMAIL_BACKEND = email_config["EMAIL_BACKEND"]

代码

要调用的代码dj_email_url.parse是这样的：


EMAIL_URL = os.environ.get("EMAIL_URL")

### Amazon SES password contains slash character,
### trying to fix resulted errors.
### Unfortunately, didn't work.
#EMAIL_URL = urllib.parse.quote(EMAIL_URL)

email_config = dj_email_url.parse(EMAIL_URL)

EMAIL_FILE_PATH = email_config["EMAIL_FILE_PATH"]
EMAIL_HOST_USER = email_config["EMAIL_HOST_USER"]
EMAIL_HOST_PASSWORD = email_config["EMAIL_HOST_PASSWORD"]
EMAIL_HOST = email_config["EMAIL_HOST"]
EMAIL_PORT = email_config["EMAIL_PORT"]
EMAIL_BACKEND = email_config["EMAIL_BACKEND"]
EMAIL_USE_TLS = email_config["EMAIL_USE_TLS"]
EMAIL_USE_SSL = email_config["EMAIL_USE_SSL"]

工作了吗？

基于@JPG的回答，我在设置环境变量时将/密码中的字符替换为：%2F

### Replace this:
export EMAIL_URL="smtp://AKIAYZT73XCKGD:BFB6UvkMgn9dniEGQZc/xM/KDS9Agc/S2@email-smtp.us-east-2.amazonaws.com:587/?tls=True"

### With this:
export EMAIL_URL="smtp://AKIAYZT73XCKGD:BFB6UvkMgn9dniEGQZc%2FxM%2FKDS9Agc%2FS2@email-smtp.us-east-2.amazonaws.com:587/?tls=True"

看起来它解决了错误而无需修改代码！需要更多的测试。

标签： pythondjangoamazon-ses

解决方案

最初，规范化您的密码部分（或包含斜杠的部分）

In [2]: from urllib.parse import quote

In [3]: pwd = "BFB6UvkMgn9dniEGQZc/xM/KDS9Agc/S2"

In [4]: quote(pwd, safe="")
Out[4]: 'BFB6UvkMgn9dniEGQZc%2FxM%2FKDS9Agc%2FS2'

现在，我们得到了规范化的密码字符串。然后，用这个新密码替换 URL 的密码部分。所以，它会变成，

export EMAIL_URL="smtp://AKIAYZT73XCKGD:BFB6UvkMgn9dniEGQZc%2FxM%2FKDS9Agc%2FS2@email-smtp.us-east-2.amazonaws.com:587/?tls=True"

例子

In [16]: from urllib.parse import unquote

In [17]: env("EMAIL_URL")
Out[17]: 'smtp://AKIAYZT73XCKGD:BFB6UvkMgn9dniEGQZc%2FxM%2FKDS9Agc%2FS2@email-smtp.us-east-2.amazonaws.com:587/?tls=True'

In [18]: env.email_url('EMAIL_URL')
Out[18]: 
{'EMAIL_FILE_PATH': '',
 'EMAIL_HOST_USER': 'AKIAYZT73XCKGD',
 'EMAIL_HOST_PASSWORD': 'BFB6UvkMgn9dniEGQZc/xM/KDS9Agc/S2',
 'EMAIL_HOST': 'email-smtp.us-east-2.amazonaws.com',
 'EMAIL_PORT': 587,
 'EMAIL_BACKEND': 'django.core.mail.backends.smtp.EmailBackend',
 'OPTIONS': {'TLS': 'True'}}

In [19]: unquote(env("EMAIL_URL"))
Out[19]: 'smtp://AKIAYZT73XCKGD:BFB6UvkMgn9dniEGQZc/xM/KDS9Agc/S2@email-smtp.us-east-2.amazonaws.com:587/?tls=True'

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