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python - 基数为 10 的 int() 的无效文字：'1044.0'

问题描述

我正在尝试在终端中运行以下代码来创建 train.record

!python convert_to_tfrecord.py -x xml -l label_map.pbtxt -o train.record -i images

其中 xml 是 xml 文件的文件夹，而 images 是原始图像的文件夹。它给了我错误：

Traceback (most recent call last):
  File "convert_to_tfrecord.py", line 165, in <module>
    tf.app.run()
  File "/usr/local/lib/python3.7/dist-packages/tensorflow/python/platform/app.py", line 40, in run
    _run(main=main, argv=argv, flags_parser=_parse_flags_tolerate_undef)
  File "/usr/local/lib/python3.7/dist-packages/absl/app.py", line 303, in run
    _run_main(main, args)
  File "/usr/local/lib/python3.7/dist-packages/absl/app.py", line 251, in _run_main
    sys.exit(main(argv))
  File "convert_to_tfrecord.py", line 152, in main
    examples = xml_to_csv(args.xml_dir)
  File "convert_to_tfrecord.py", line 82, in xml_to_csv
    int(root.find('size')[0].text),
ValueError: invalid literal for int() with base 10: '1044.0'

convert_to_tfrecord.py 的相关代码是：

def xml_to_csv(path):
    """Iterates through all .xml files (generated by labelImg) in a given directory and combines
    them in a single Pandas dataframe.
    Parameters:
    ----------
    path : str
        The path containing the .xml files
    Returns
    -------
    Pandas DataFrame
        The produced dataframe
    """

    xml_list = []
    for xml_file in glob.glob(path + '/*.xml'):
        tree = ET.parse(xml_file)
        root = tree.getroot()
        for member in root.findall('object'):
            value = (root.find('filename').text,
                     int(root.find('size')[0].text),
                     int(root.find('size')[1].text),
                     member[0].text,
                     int(member[4][0].text),
                     int(member[4][1].text),
                     int(member[4][2].text),
                     int(member[4][3].text)
                     )
            xml_list.append(value)
    column_name = ['filename', 'width', 'height',
                   'class', 'xmin', 'ymin', 'xmax', 'ymax']
    xml_df = pd.DataFrame(xml_list, columns=column_name)
    return xml_df

似乎是宽度错误，但我不知道该如何解决。感谢任何帮助！

编辑：我刚刚尝试过 int(float(...))，但它仍然无法修复错误

标签： pythonobject-detection

解决方案

你的号码是十进制字符串

因此，首先，您需要先转换为浮点数，然后再转换为整数，因为它有小数点。

def xml_to_csv(path):
    """Iterates through all .xml files (generated by labelImg) in a given directory and combines
    them in a single Pandas dataframe.
    Parameters:
    ----------
    path : str
        The path containing the .xml files
    Returns
    -------
    Pandas DataFrame
        The produced dataframe
    """

    xml_list = []
    for xml_file in glob.glob(path + '/*.xml'):
        tree = ET.parse(xml_file)
        root = tree.getroot()
        for member in root.findall('object'):
            value = (root.find('filename').text,
                     int(float(root.find('size')[0].text)),
                     int(float(root.find('size')[1].text)),
                     member[0].text,
                     int(float(member[4][0].text)),
                     int(float(member[4][1].text)),
                     int(float(member[4][2].text)),
                     int(float(member[4][3].text))
                     )
            xml_list.append(value)
    column_name = ['filename', 'width', 'height',
                   'class', 'xmin', 'ymin', 'xmax', 'ymax']
    xml_df = pd.DataFrame(xml_list, columns=column_name)
    return xml_df

例如：

>>> int('1044.0')
Traceback (most recent call last):
  File "<pyshell#0>", line 1, in <module>
    int('1044.0')
ValueError: invalid literal for int() with base 10: '1044.0'
>>> int(float('1044.0'))
1044

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