c++ - C++primer 5ed 1.23 和 1.4.4 中的示例有不同的输出
问题描述
这是 1.4.4 中的代码
#include<iostream>
int main()
{
int currval=0,val=0;
if(std::cin>>currval){
int cnt=1;
while(std::cin>>val){
if(val==currval){
++cnt;
}
else{
std::cout<<currval<<" occurs "
<<cnt<<" times "<<std::endl;
currval = val;
cnt=1;
}
}
std::cout<<currval<<" occurs "
<<cnt<<" times "<<std::endl;
}
return 0;
}
这是实践中的代码 1.23
#include<iostream>
#include"Sales_item.hpp"
int main()
{
Sales_item curbok;
Sales_item bok;
if(std::cin>>curbok)
{
int cnt=1;
while(std::cin>>bok)
{
if (bok.isbn() == curbok.isbn())
{
++cnt;
}
else
{
std::cout<<"Total selling of "
<<curbok.isbn()<<" is "<<cnt
<<std::endl;
curbok = bok;
cnt = 1;
}
}
std::cout<<"Total selling of"
<<curbok.isbn()<<" is "<<cnt<<std::endl;
std::cout<<"222"<<std::endl;
}
return 0;
}
我认为他们有类似的过程来实现功能。但在第一个代码中:
型号 1 1 1 2 2 2
键入 Ctrl+Z
输出答案
1 occurs 3 times 2 occurs 3 times
在第二个代码中
- 类型 202-x 2 2、202-x 2 2、203 - x 2 2
- 键入 Ctrl+Z 并按 Enter
- 输出答案
Total selling of 202-x is 2
- 再次键入 Ctrl+z 并按 Enter
- 输出剩下的答案
Total selling of 203-x is 1
为什么第二个代码需要按两次 Ctrl+Z 才能结束流
我在Windows10系统中运行VScode和MinGW-x64 g++中的代码
1.23 代码中包含的 Sales_item.hpp:
#ifndef SALESITEM_H
// we're here only if SALESITEM_H has not yet been defined
#define SALESITEM_H
#include "Version_test.hpp"
// Definition of Sales_item class and related functions goes here
#include <iostream>
#include <string>
class Sales_item {
// these declarations are explained section 7.2.1, p. 270
// and in chapter 14, pages 557, 558, 561
friend std::istream& operator>>(std::istream&, Sales_item&);
friend std::ostream& operator<<(std::ostream&, const Sales_item&);
friend bool operator<(const Sales_item&, const Sales_item&);
friend bool
operator==(const Sales_item&, const Sales_item&);
public:
// constructors are explained in section 7.1.4, pages 262 - 265
// default constructor needed to initialize members of built-in type
#if defined(IN_CLASS_INITS) && defined(DEFAULT_FCNS)
Sales_item() = default;
#else
Sales_item(): units_sold(0), revenue(0.0) { }
#endif
Sales_item(const std::string &book):
bookNo(book), units_sold(0), revenue(0.0) { }
Sales_item(std::istream &is) { is >> *this; }
public:
// operations on Sales_item objects
// member binary operator: left-hand operand bound to implicit this pointer
Sales_item& operator+=(const Sales_item&);
// operations on Sales_item objects
std::string isbn() const { return bookNo; }
double avg_price() const;
// private members as before
private:
std::string bookNo; // implicitly initialized to the empty string
#ifdef IN_CLASS_INITS
unsigned units_sold = 0; // explicitly initialized
double revenue = 0.0;
#else
unsigned units_sold;
double revenue;
#endif
};
// used in chapter 10
inline
bool compareIsbn(const Sales_item &lhs, const Sales_item &rhs)
{ return lhs.isbn() == rhs.isbn(); }
// nonmember binary operator: must declare a parameter for each operand
Sales_item operator+(const Sales_item&, const Sales_item&);
inline bool
operator==(const Sales_item &lhs, const Sales_item &rhs)
{
// must be made a friend of Sales_item
return lhs.units_sold == rhs.units_sold &&
lhs.revenue == rhs.revenue &&
lhs.isbn() == rhs.isbn();
}
inline bool
operator!=(const Sales_item &lhs, const Sales_item &rhs)
{
return !(lhs == rhs); // != defined in terms of operator==
}
// assumes that both objects refer to the same ISBN
Sales_item& Sales_item::operator+=(const Sales_item& rhs)
{
units_sold += rhs.units_sold;
revenue += rhs.revenue;
return *this;
}
// assumes that both objects refer to the same ISBN
Sales_item
operator+(const Sales_item& lhs, const Sales_item& rhs)
{
Sales_item ret(lhs); // copy (|lhs|) into a local object that we'll return
ret += rhs; // add in the contents of (|rhs|)
return ret; // return (|ret|) by value
}
std::istream&
operator>>(std::istream& in, Sales_item& s)
{
double price;
in >> s.bookNo >> s.units_sold >> price;
// check that the inputs succeeded
if (in)
s.revenue = s.units_sold * price;
else
s = Sales_item(); // input failed: reset object to default state
return in;
}
std::ostream&
operator<<(std::ostream& out, const Sales_item& s)
{
out << s.isbn() << " " << s.units_sold << " "
<< s.revenue << " " << s.avg_price();
return out;
}
double Sales_item::avg_price() const
{
if (units_sold)
return revenue/units_sold;
else
return 0;
}
#endif
解决方案
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