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ios - 深层链接不包含有效的必需参数

问题描述

我正在尝试将 firebase 动态链接集成到 React Native 应用程序中，当我导航到前缀 url 时，我看到了正确的 json 对象，表明初始域设置成功。我已根据文档将关联的域添加到我的项目中。我遇到的问题是，当我打开使用 dynamiclinks sdk 创建的链接之一时，我在 xcode 中收到此错误。

 [Firebase/Analytics][I-ACS023001] Deep Link does not contain valid required params. URL params: {
    socialDescription = "Check out business name on our app";
    socialImageUrl = "http://[apiurl]//rails/active_storage/blobs/eyJfcmFpbHMiOnsibWVzc2FnZSI6IkJBaHBCZz09IiwiZXhwIjpudWxsLCJwdXIiOiJibG9iX2lkIn19--046e60135790b0344b8ac127c4e8bcf8ad7cd216/cover.png";
    socialTitle = "\"Business name\" on our app";
}

这就是我创建链接的方式..

            const link = await dynamicLinks().buildShortLink({
            link:'https://myapp.page.link/id=${props.business.id}',
            domainUriPrefix: 'https://myApp.page.link',
            ios: {
                bundleId: 'com.myApp.app',
                appStoreId: '123456589',
                minimumVersion: '12',
              },
            social: {
                imageUrl: `${API_URL}${cover_image}`,
                title: `"Check out ${props.business.name}" on our app`,
                descriptionText: `Check out ${props.business.name} on our app`,
              },
            });

            Share.share({
              url: link,
              title: 'Check this out!',
            });

这是我添加到 appdelegate 以处理传入链接的内容


- (BOOL)application:(UIApplication *)application
continueUserActivity:(nonnull NSUserActivity *)userActivity
 restorationHandler:
#if defined(__IPHONE_12_0) && (__IPHONE_OS_VERSION_MAX_ALLOWED >= __IPHONE_12_0)
(nonnull void (^)(NSArray<id<UIUserActivityRestoring>> *_Nullable))restorationHandler {
#else
    (nonnull void (^)(NSArray *_Nullable))restorationHandler {
#endif  // __IPHONE_12_0
  BOOL handled = [[FIRDynamicLinks dynamicLinks] handleUniversalLink:userActivity.webpageURL                                           completion:^(FIRDynamicLink * _Nullable dynamicLink,                                                  NSError * _Nullable error) {
 // ...           }];
  return handled;
}
  
  
  - (BOOL)application:(UIApplication *)app
              openURL:(NSURL *)url
              options:(NSDictionary<NSString *, id> *)options {
    return [self application:app
                     openURL:url
           sourceApplication:options[UIApplicationOpenURLOptionsSourceApplicationKey]
                  annotation:options[UIApplicationOpenURLOptionsAnnotationKey]];
  }

  - (BOOL)application:(UIApplication *)application
              openURL:(NSURL *)url
    sourceApplication:(NSString *)sourceApplication
           annotation:(id)annotation {
    FIRDynamicLink *dynamicLink = [[FIRDynamicLinks dynamicLinks] dynamicLinkFromCustomSchemeURL:url];

    if (dynamicLink) {
      if (dynamicLink.url) {
        // Handle the deep link. For example, show the deep-linked content,
        // apply a promotional offer to the user's account or show customized onboarding view.
        // ...
      } else {
        // Dynamic link has empty deep link. This situation will happens if
        // Firebase Dynamic Links iOS SDK tried to retrieve pending dynamic link,
        // but pending link is not available for this device/App combination.
        // At this point you may display default onboarding view.
      }
      return YES;
    }
    return NO;
  }

这是相应的反应本机代码

  const handleDynamicLink = link => {
    // Handle dynamic link inside your own application
    console.log(' ', link);
  };

  useEffect(() => {
    const unsubscribe = dynamicLinks().onLink(handleDynamicLink);
    // When the component unmounts, remove the listener
    return unsubscribe;
  }, []);

当我在没有社交元数据的情况下建立链接时，它可以工作，但是链接没有图像。熟悉firebase动态链接的人可以告诉我这里有什么问题吗？链接缺少什么参数？

标签： iosfirebasereact-nativefirebase-dynamic-links

解决方案

对于那些最终遇到同样问题的人，我发现了这里发生的事情：

https://github.com/invertase/react-native-firebase/issues/3182

最后一条评论说：

当使用 url（而不是消息）字段中传递的链接直接共享到 iMessage 时，Apple 会解析链接，但 url 路径会被动态链接中的社交字段中的数据替换，这会使链接格式错误。

我的解决方案是使用“react-native-share”库而不是像这样的本机共享扩展

const url = `${link}`;
const message = `"${props.business.name}" on our app`;
const options = Platform.select({
              ios: {
                activityItemSources: [
                  {
                    placeholderItem: {
                      type: 'text',
                      content: `${message} ${url}`,
                    },
                    item: {
                      default: {
                        type: 'text',
                        content: `${message} ${url}`,
                      },
                    },
                    linkMetadata: {
                      title: `"${props.business.name}" on our app`,
                    },
                  },
                ],
              },
              default: {
                message: `${message} ${url}`,
              },
});

Share.open(options)
.then(res => {
                console.log(res);
})
.catch(err => {
                console.log(err);
});

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