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python - Python 3 正则表达式租赁 DHCP

问题描述

我在 DHCP 租用文件中有以下信息

lease 201.249.14.226 { 
  starts epoch 1586469086; # Thu Apr 09 17:51:26 2020
  ends epoch 1587765086; # Fri Apr 24 17:51:26 2020
  tstp epoch 1587765086; # Fri Apr 24 17:51:26 2020
  cltt epoch 1586469086; # Thu Apr 09 17:51:26 2020
  binding state free;
  next binding state free;
  rewind binding state free;
  hardware ethernet f8:d1:11:50:1c:2b;
  set vendor-class-identifier = "MSFT 5.0";
  client-hostname "TL-MR3420";
}
lease 201.249.11.68 {
  starts epoch 1586469229; # Thu Apr 09 17:53:49 2020
  ends epoch 1587765229; # Fri Apr 24 17:53:49 2020
  tstp epoch 1587765229; # Fri Apr 24 17:53:49 2020
  cltt epoch 1586469440; # Thu Apr 09 17:57:20 2020
  binding state active;
  next binding state free;
  rewind binding state free;
  hardware ethernet 34:4d:ea:fa:9d:10;
  option agent.circuit-id "mil-bras-06--172.26.22.237 trunk 0/1/0/2:427.32";
  client-hostname "ZTE";
}
lease 201.249.11.199 {
  starts epoch 1586469229; # Thu Apr 09 17:53:49 2020
  ends epoch 1587765229; # Fri Apr 24 17:53:49 2020
  tstp epoch 1587765229; # Fri Apr 24 17:53:49 2020
  cltt epoch 1586469440; # Thu Apr 09 17:57:20 2020
  binding state active;
  next binding state free;
  rewind binding state free;
  hardware ethernet 34:4d:ea:fa:9d:10;
  option agent.circuit-id "cnt-bras-07--172.26.220.225 trunk 0/1/0/2:427.20";
  client-hostname "ZTE";
}

是一个缩减样本

当且仅当“绑定状态处于活动状态”时，我需要在应用 Python re 后获取；

下一个：

lease 201.249.11.68
binding state active;
hardware ethernet 34: 4d: ea: fa: 9d: 10;
option agent.circuit-id "mil-bras-06--172.26.22.237 trunk 0/1/0/2: 427.32";
client-hostname "ZTE";

lease 201.249.11.199
binding state active;
hardware ethernet 34: 4d: ea: fa: 9d: 10;
option agent.circuit-id "cnt-bras-07--172.26.220.225 trunk 0/1/0/2: 427.20";
client-hostname "ZTE";

不强制使用python模块（正则表达式）不知道有没有更好的思路或者替代方案

我正在这样做...

import re
with open('/var/lib/dhcp.leases', 'r') as f:
    #pattern = re.compile(r'((option agent.circuit-id)\s"(\w{3}-\w{4}-\d{2}\W{2}))')
    #pattern = re.compile(r'(\W{2}((\d{0,3}).(\d{0,3}).(\d{0,3}).(\d{0,3})\s\w{5}\s[0-9/]{7}:\d{1,3}.\d{1,3}"))')(
    #pattern = re.compile(r'(lease [0-9.]+)')
    #pattern = re.compile(r'binding state active;')
    #pattern = re.compile(r'(hardware ethernet).(\w{2}:\w{2}:\w{2}:\w{2}:\w{2}:\w{2})')
    #pattern = re.compile(r'(option agent.circuit-id)\s["]+(\w{3}-\w{4}-\d{2}\W{2}\d{1,3}[.]\d{1,3}[.]\d{1,3}.*?)')
    contents = f.read()
    matches = pattern.finditer(contents)
    for match in matches:
        print(match)

我有几种单独的模式来查找结果，但我不知道如何将它们组合在一起以满足条件

当且仅当“绑定状态处于活动状态；”

标签： pythonpython-3.8re

解决方案

我们可以re.findall在这里尝试使用正则表达式模式，该模式针对并捕获所需的文本：

matches = re.findall(r'(lease \d+(?:\.\d+){3}) \{[^}]+(binding state active;)[^}]+(hardware[^}]+option[^}]+client[^;]+)', inp)
output = ['\n'.join(x) for x in matches]
print(output)

这打印：

['lease 201.249.11.68\nbinding state active;\nhardware ethernet 34:4d:ea:fa:9d:10;\n  option agent.circuit-id "mil-bras-06--172.26.22.237 trunk 0/1/0/2:427.32";\n  client-hostname "ZTE"',
 'lease 201.249.11.199\nbinding state active;\nhardware ethernet 34:4d:ea:fa:9d:10;\n  option agent.circuit-id "cnt-bras-07--172.26.220.225 trunk 0/1/0/2:427.20";\n  client-hostname "ZTE"']

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