conda - Conda 4.10.3 和 Snakemake >5 "__conda_exe" 问题
问题描述
我有以下问题,当我使用下面的命令时,snakemake 似乎无法使用 --use-conda 选项解决环境的创建问题。
如果我不使用snakemake的这个选项并在由conda而不是snakemake创建的适当环境中启动snakefile,则命令执行是可以的。
有人有同样的问题吗?
谢谢,
命令:
snakemake -p -d ./ -s 00_Quality_Check.smk -j 4 --use-conda
版本:
- 康达 4.10.3
- 蟒蛇3.9
- 蛇制造 5.11
错误信息:
Building DAG of jobs...
CreateCondaEnvironmentException:
Unable to check conda version:
environment: ligne 10: __conda_exe : commande introuvable
File "/home/usr/miniconda3/envs/snake/lib/python3.9/site-packages/snakemake/deployment/conda.py", line 232, in create
File "/home/usr/miniconda3/envs/snake/lib/python3.9/site-packages/snakemake/deployment/conda.py", line 343, in __new__
File "/home/usr/miniconda3/envs/snake/lib/python3.9/site-packages/snakemake/deployment/conda.py", line 356, in __init__
File "/home/usr/miniconda3/envs/snake/lib/python3.9/site-packages/snakemake/deployment/conda.py", line 410, in _check
版本:
- 康达 4.10.3
- 蟒蛇3.9
- 蛇制造 6.7
错误信息:
Building DAG of jobs...
environment: ligne 10: __conda_exe : commande introuvable
Traceback (most recent call last):
File "/home/usr/miniconda3/envs/snake/lib/python3.9/site-packages/snakemake/__init__.py", line 699, in snakemake
success = workflow.execute(
File "/home/usr/miniconda3/envs/snake/lib/python3.9/site-packages/snakemake/workflow.py", line 933, in execute
dag.create_conda_envs(
File "/home/usr/miniconda3/envs/snake/lib/python3.9/site-packages/snakemake/dag.py", line 304, in create_conda_envs
env.create(dryrun)
File "/home/usr/miniconda3/envs/snake/lib/python3.9/site-packages/snakemake/deployment/conda.py", line 281, in create
conda = Conda(self._container_img)
File "/home/usr/miniconda3/envs/snake/lib/python3.9/site-packages/snakemake/deployment/conda.py", line 433, in __init__
shell.check_output(self._get_cmd("conda info --json"))
File "/home/usr/miniconda3/envs/snake/lib/python3.9/site-packages/snakemake/shell.py", line 63, in check_output
return sp.check_output(cmd, shell=True, executable=executable, **kwargs)
File "/home/usr/miniconda3/envs/snake/lib/python3.9/subprocess.py", line 424, in check_output
return run(*popenargs, stdout=PIPE, timeout=timeout, check=True,
File "/home/usr/miniconda3/envs/snake/lib/python3.9/subprocess.py", line 528, in run
raise CalledProcessError(retcode, process.args,
subprocess.CalledProcessError: Command 'conda info --json' returned non-zero exit status 127.
解决方案
这可能与这个长期开放的 conda 问题有关:
https://github.com/conda/conda/issues/7980
基本上,默认情况下您不能从脚本中运行 conda。
为了解决这个问题,以前人们在他们的 ~/.bashrc 或 ~/.bash_profile 中放在 conda 节之后(即,在 "# <<< conda initialize <<<" 之后):
# Make these functions available to scripts.
export -f conda
export -f __conda_activate
export -f __add_sys_prefix_to_path
export -f __conda_hashr
但看起来 conda 中的某些内容最近发生了变化。现在以下可能就足够了:
# Make these functions available to scripts.
export -f conda
export -f __conda_activate
export -f __conda_reactivate
export -f __conda_exe
如果这些都不起作用,只需使用大锤:
# Make these functions available to scripts.
export -f conda
export -f __conda_activate
export -f __conda_reactivate
export -f __add_sys_prefix_to_path
export -f __conda_hashr
export -f __conda_exe
执行上述操作有助于修复上面为同事报告的相同错误。
重要提示:您需要注销并重新登录才能正常工作。
要进行测试,请将“conda info --json”放入脚本中,然后运行该脚本。如果您看到一堵 JSON 墙,那么您已经解决了问题。
推荐阅读
- javascript - VueJS:属性或方法......未在实例上定义,但在渲染期间引用
- c++ - 如何将 QPrinter 绘图保存为 QPixmap 并将其设置为窗口图标上的 QIcon?
- apache-spark - Spark中来自关系数据模型的树/嵌套结构
- python - 查找字符串中的最后一个子字符串?
- html - 如何调整 inline-block 布局中元素之间的间距?
- r - How to select strings in a nested list from a list of indexes
- flutter - 如何将图像部分显示为颤动以获得拉幕效果?
- anaconda - 使用 python-pptx 的 ImportError
- ruby - 如何在 ruby on rails 上使用我的小课堂
- java - 清单合并失败 (AppIntro)