javascript - 从查询字符串中删除关联数组

Question

我喜欢conditions从查询string中删除一个数组变量，它将是window.location.search.

• 第一个输出Before是初始字符串。
• 二是删除后sub
• 第三个还包含conditions。

我怎样才能摆脱它？

编辑 未编码的字符串是

conditions[0][0][field]=firstname&conditions[0][0][operator]=is&conditions[0][0][value]=John&conditions[1][0][field]=lastname&conditions[1][0][operator]=is&conditions[1][0][value]=Doe

这是应用程序所需要的。

var string = '?page=foo&sub=bar&conditions%5B0%5D%5B0%5D%5Bfield%5D=firstname&conditions%5B0%5D%5B0%5D%5Boperator%5D=is&conditions%5B0%5D%5B0%5D%5Bvalue%5D=John&conditions%5B1%5D%5B0%5D%5Bfield%5D=lastname&conditions%5B1%5D%5B0%5D%5Boperator%5D=is&conditions%5B1%5D%5B0%5D%5Bvalue%5D=Doe';
var params = new URLSearchParams(string);

console.log('Before', params.toString());

params.delete('sub');

console.log('remove sub works', params.toString());

params.delete('conditions');

console.log('conditions still exist', params.toString());

标签： javascripturlsearchparams

Answer 1

你想要这个吗？

var string =
  "?page=foo&sub=bar&conditions%5B0%5D%5B0%5D%5Bfield%5D=firstname&conditions%5B0%5D%5B0%5D%5Boperator%5D=is&conditions%5B0%5D%5B0%5D%5Bvalue%5D=John&conditions%5B1%5D%5B0%5D%5Bfield%5D=lastname&conditions%5B1%5D%5B0%5D%5Boperator%5D=is&conditions%5B1%5D%5B0%5D%5Bvalue%5D=Doe";
const urlSearchParams = new URLSearchParams(string);

const params = Object.fromEntries(urlSearchParams.entries());

console.log({ params });

function getFilteredParams(params, filteredString) {
  let obj = {};
  for (const key in params) {
    if (key.indexOf(filteredString) == -1) {
      obj[key] = params[key];
    }
  }
  return obj;
}

console.log(getFilteredParams(params, "conditions"));