javascript - 如何将嵌套对象展平为对象数组

Question

我需要将嵌套对象展平为对象数组。到目前为止，这就是我想出的。但它不能正常工作。目前我正在检查当前元素是否为对象，如果它是我递归调用相同函数的对象。

作为输出我需要这个。

[
 {title: 'Foo', value: 111},
 {title: 'Bar', value: 222},
 ...
]

var data = {
  1: {
    title: "Foo",
    value: 111,
    children: {
      2: {
        title: "Bar",
        value: 222,
      },
    },
  },
  3: {
    title: "Baz",
    value: 333,
    children: {
      4: {
        title: "Qux",
        value: 444,
        children: {
          5: {
            title: "Quux",
            value: 555,
          },
        },
      },
    },
  },
};

const finalArrayOfObjects = [];

  const flattenObject = (obj) => {
    const flattened = {};

    Object.keys(obj).forEach((key) => {
      if (typeof obj[key] === "object" && obj[key] !== null) {
        flattenObject(obj[key]);
      } else {
        flattened[key] = obj[key];
      }

      finalArrayOfObjects.push(flattened);
      console.log(flattened);
    });
  };

标签： javascript

Answer 1

是时候再次证明 函数式编程和递归的力量了

var data = {
        1: {
          title: "Foo",
          value: 111,
          children: {
            2: {
              title: "Bar",
              value: 222,
            },
          },
        },
        3: {
          title: "Baz",
          value: 333,
          children: {
            4: {
              title: "Qux",
              value: 444,
              children: {
                5: {
                  title: "Quux",
                  value: 555,
                },
              },
            },
          },
        },
      };

  const dictAsArray = Object.values(data);
  const flat = [];

  function drill(array) {
    array.map(obj => {
       recursiveCall(obj);
      });
   }

  function recursiveCall(obj) {
    if (obj.children) {
      const children = JSON.parse(JSON.stringify(Object.values(obj.children)));
      delete obj.children; 
      drill(children);
    }

    flat.push(obj);
  }

  dictAsArray.map(dict => recursiveCall(dict));
  console.log(flat);

在这种方法中，子对象从每个对象中移除。如果您希望它们保留，您可以简单地删除delete obj.children.