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问题描述

我有一个查询来获取用户,该表与其他 3 个相关,但查询有点长,我想处理 JsonResource 但我无法生成 JsonResource,因为我有它正常查询。

方法索引:

public function index()
{
    $users = User::select('users.id', 'users.name', 'users.email', 'users.username', 'users.status', 'users.id_cost_center', 'cost_centers.code AS code_cost_center', 'cost_centers.description AS cost_center', 
                          'users.id_dependence', 'dependencies.description AS dependence', 'users.id_profile', 'profiles.name AS profile', 'users.created_at')
                        ->join('cost_centers', 'users.id_cost_center', '=', 'cost_centers.id')
                        ->join('dependencies', 'users.id_dependence', '=', 'dependencies.id')
                        ->join('profiles', 'users.id_profile', '=', 'profiles.id')                            
                        ->orderBy('users.created_at', 'desc')
                        ->get();

    $message = $this->sendResponse($users, 'List of users');

    return $message;
}

我的用户模型中的关系:

public function cost_center()
{
     return $this->belongsTo(CostCenter::class, 'id_cost_center');
}  


public function dependence()
{
    return $this->belongsTo(Dependence::class, 'id_dependence');
}


public function profile() {
    return $this->belongsTo(Profile::class, 'id_profile');
}

其他表中的关系:

成本中心:

public function users()
{
    return $this->hasMany(User::class, 'id_cost_center');
}

依赖:

public function users()
{
   return $this->hasMany(User::class, 'id_dependence');
}

轮廓:

public function users() 
{
   return $this->hasMany(User::class, 'id_profile');
}

回复:

{
"success": true,
"data": [
    {
        "id": 1,
        "name": "admin",
        "email": "admin@gmail.com",
        "username": "admin",
        "status": 1,
        "id_cost_center": 1,
        "code_cost_center": "001",
        "cost_center": "Admin",
        "id_dependence": 1,
        "dependence": "System",
        "id_profile": 1,
        "profile": "Developer",
        "created_at": "2021-09-13T11:26:46.000000Z"
    },
    {
        "id": 2,
        "name": "user",
        "email": "user@gmail.com",
        "username": "user",
        "status": 1,
        "id_cost_center": 2,
        "code_cost_center": "002",
        "cost_center": "Service",
        "id_dependence": 2,
        "dependence": "Store",
        "id_profile": 2,
        "profile": "Aux",
        "created_at": "2021-09-13T11:26:46.000000Z"
    }
],
"message": "List of users"

}

我试图创建一个用户集合类,但它只生成用户而不是关系:

public function toArray($request)
{
    return [
        'data' => $this->collection,
    ];
}

它只向我显示用户数据,我希望能够得到与第一次正常查询相同的答案。

标签: jsonlaravelapi

解决方案


你可以做的3件事:

  1. 调用用户模型时始终返回关系:
class User extends Model {

    protected $with = ['cost_center', 'profile', 'dependence'];

    // ...
}

这将始终返回具有关系的用户。

  1. 仅在使用时返回关系toArray
public function toArray($request)
{
    return [
        'data' => $this->collection->with('cost_center'),
    ];
}
  1. 只需在控制器中执行此操作。
    $users = User::with('cost_center', 'profile', 'dependance')->get();

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