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python - python 中的骰子模拟与无限的可定制骰子？

问题描述

我正在研究经典的“在 python 中构建一个骰子模拟”学校项目，我试图让它变得非常复杂。基本上，我正在尝试的是一种方法，当你按下一个按钮时，我不想滚动一个 n 面 x 次的骰子，我想滚动 x 个骰子，每个骰子都有自己的面数。我对python一窍不通，所以我什至不知道这是否可能。据我所知，它似乎需要大量的变量，因为在创建信息时没有真正的方法可以“保存”信息。这是我的代码，它确实有效：

from random import randint

stop="c"
dicenumb=0

print ("Automatic Dice Roller")

while stop !="x":
    if stop == "c":
        print ("Type how many dice you want to roll, then press enter.")
        d=input("")
        print ("Type how many sides you want each dice to have, then press enter.")
        s=input("")
        print("rolling %s dice with %s side(s)!" % (d,s))
    for x in range (0,int(d)):
        dicenumb += 1
        print("Dice # %s is...%s!" % (dicenumb,randint(1,int(s))))
    dicenumb=0
    print("Press enter to roll, c then enter to change the amount of dice and sides, or x then enter to exit!")
    stop=input("")

这是我正在处理的代码，以便尝试这样做：

from random import randint

stop="c"
dicenumb=0
dicecust=0
print ("Automatic Dice Roller")

while stop !="x":
    if stop == "c":
        print ("if you want to enter the values of each dice individually, press i, then enter. Otherwise, press enter")
        ind=input("")
        if ind != "i":
            print ("Type how many dice you want to roll, then press enter.")
            d=input("")
            print ("Type how many sides you want each dice to have, then press enter.")
            s=input("")
            print("rolling %s dice with %s side(s)!" % (d,s))
            for x in range (0,int(d)):
                dicenumb += 1
                print("Dice # %s is...%s!" % (dicenumb,randint(1,int(s))))
            dicenumb=0
        else
            for x in range (0,int(d)):
                print ("how many dice would you like to roll? maximum of 10.")
                custnumb=input("")
                dicecust += 1
                print "how many sides would you like dice #%s to have?" % dicecust 
    print("Press enter to roll, c then enter to change the amount of dice and sides, or x then enter to exit!")
    stop=input("")

标签： pythonpython-3.x

解决方案

建立一个你想要掷骰子的列表，然后遍历这个列表：

from random import randint

n = int(input("How many dice would you like to roll?\n"))
dice = [
    int(input(f"How many sides would you like die #{i} to have?\n"))
    for i in range(1, n + 1)
]
for i, die in enumerate(dice, 1):
    print(f"Die #{i} is... {randint(1, die)}!")

How many dice would you like to roll?
6
How many sides would you like die #1 to have?
4
How many sides would you like die #2 to have?
100
How many sides would you like die #3 to have?
6
How many sides would you like die #4 to have?
6
How many sides would you like die #5 to have?
20
How many sides would you like die #6 to have?
100
Die #1 is... 1!
Die #2 is... 51!
Die #3 is... 4!
Die #4 is... 6!
Die #5 is... 9!
Die #6 is... 57!

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