时间戳

首页 > 解决方案 > 在没有“后端终止”消息的情况下在循环中打开和关闭 pygame 窗口

python - 在没有“后端终止”消息的情况下在循环中打开和关闭 pygame 窗口

问题描述

我正在为学校开发一个程序，并且需要使用 pygame 窗口来显示我的程序的累积总数（用于订购咖啡）。以下是窗口打开部分的代码：

if totalconf == 'y':
    # if user wishes to view cumulative totals
        pygame.init()
        background_colour = (231,247,146)
        (width, height) = (1500, 900)
        screen = pygame.display.set_mode((width, height))
        pygame.display.set_caption('Running Totals')
        # initialise new window with yellow background and title
        myFont = pygame.font.SysFont("arial", 40)
        myFont2 = pygame.font.SysFont("arial", 20)
        # initialise small and large fonts
        text = myFont.render("In store totals:", True, (0, 0, 0))
        text3 = myFont.render("Takeaway totals:", True, (0, 0, 0))
        text4 = myFont.render("In store earnings:", True, (0, 0, 0))
        text5 = myFont.render("Takeaway earnings:", True, (0, 0, 0))
        text6 = myFont.render(f"Total discounts: ${total_discounts}", True, (0, 0, 0))
        text7 = myFont.render(f"Total gst: ${total_gst}", True, (0, 0, 0))
        text8 = myFont.render(f"Total surcharges: ${total_takeawaycharges}", True, (0, 0, 0))
        # initialise headings and totals to display on screen
        screen.fill(background_colour)
        # fill screen with background color
        pygame.display.flip()
        # update screen
        running = True
        # run window
        while running:
        # while window is running
            screen.blit(text, (20, 20))
            screen.blit(text3, (300, 20))
            screen.blit(text4, (600, 20))
            screen.blit(text5, (900, 20))
            screen.blit(text6, (20, 700))
            screen.blit(text7, (20, 740))
            screen.blit(text8, (20, 780))
            # project all text onto screen
            pygame.display.update()
            # update screen
            initial = 70
            # set initial as 70 down 
            for item, values in totalsdict.items():
            # for values stored in totals dict
                text2 = myFont2.render(f'{item.title()}: {values[0]}', True, (0,0,0))
                # print out item and equivalent total in small font
                screen.blit(text2, (20, initial))
                # display text on screen
                pygame.display.update()
                # update screen
                initial += 40
                # increase inital by 40 so values print vertically down
            initial = 70
            # set initial as 70 down 
            for item, values in totalsdict.items():
            # for values stored in totals dict
                text2 = myFont2.render(f'{item.title()}: {values[1]}', True, (0,0,0))
                # print out item and equivalent total in small font
                screen.blit(text2, (300, initial))
                # display text on screen
                pygame.display.update()
                # update screen
                initial += 40
                # increase inital by 40 so values print vertically down
            initial = 70
            # set initial as 70 down 
            for item, values in totalsdict.items():
            # for values stored in totals dict
                text2 = myFont2.render(f'{item.title()}: {values[2]}', True, (0,0,0))
                # print out item and equivalent total in small font
                screen.blit(text2, (600, initial))
                # display text on screen
                pygame.display.update()
                # update screen
                initial += 40
                # increase inital by 40 so values print vertically down
            initial = 70
            # set initial as 70 down 
            for item, values in totalsdict.items():
            # for values stored in totals dict
                text2 = myFont2.render(f'{item.title()}: {values[3]}', True, (0,0,0))
                # print out item and equivalent total in small font
                screen.blit(text2, (900, initial))
                # display text on screen
                pygame.display.update()
                # update screen
                initial += 40
                # increase inital by 40 so values print vertically down
            for event in pygame.event.get():
                if event.type == pygame.QUIT:
                    running = False
                if running == False:
                    pygame.quit()
                # code to stop running if 'X' is pressed

如果用户想查看累计总数，他们输入“y”作为 totalconf。这段代码位于一个连续的 while 循环中，该循环接受命令，直到输入一个空白。程序第一次运行时效果很好，可以在不停止程序的情况下打开和关闭。但是，第二次，如果我希望查看更新的累积总数并打开 pygame 窗口，我会收到一条消息，上面写着“后端终止或断开连接。Windows 致命异常：访问冲突”。这是一个非常长的程序，但我希望我提供的信息已经足够了。

所以总而言之，我需要能够在每次循环运行时打开和关闭窗口而不会收到上面的消息。

标签： pythonpygame

解决方案

使用键盘事件：

for event in pygame.event.get():
    if event.type == pygame.QUIT:
        running = False
    if event.type == pygame.KEYDOWN:
        if event.key == pygame.K_x:
            running = False

键盘事件（参见pygame.event模块）仅在按键状态更改时发生一次。KEYDOWN每次按下某个键时，该事件发生一次。KEYUP每次释放键时发生一次。将键盘事件用于单个操作。

推荐阅读