java - 无法使用 Android 应用通过 API 下载数据
问题描述
我尝试通过 API 将应用程序与我的网站链接,但发生错误并且活动中未显示任何数据。它只显示一个包含数据的 Toast 消息和一个句子: (Toast.makeText(getApplicationContext(), "Json parsing error: " + e.getMessage(), Toast.LENGTH_LONG).show();
请帮我解决这个错误或给我任何改进它的提示
注意:我在互联网上找到的带有许可证 CC4 的代码,在修改之前它可以正常工作
谢谢
<?xml version="1.0" encoding="utf-8"?>
<androidx.constraintlayout.widget.ConstraintLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:app="http://schemas.android.com/apk/res-auto"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
tools:context=".API.Other1_1.API_Test_1_1">
<ListView
android:id="@+id/list"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
app:layout_constraintEnd_toEndOf="parent"
app:layout_constraintStart_toStartOf="parent"
app:layout_constraintTop_toTopOf="parent" />
</androidx.constraintlayout.widget.ConstraintLayout>
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:orientation="vertical"
>
<TextView
android:id="@+id/Name"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:paddingBottom="2dip"
android:textColor="@color/colorAccent" />
<TextView
android:id="@+id/Roll"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:textColor="#5d5d5d"
android:textStyle="bold" />
</LinearLayout>
public class API_HttpHandler_1_1 {
private static final String TAG = API_HttpHandler_1_1.class.getSimpleName();
public API_HttpHandler_1_1() {
}
public String makeServiceCall(String reqUrl) {
String response = null;
try {
URL url = new URL(reqUrl);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("GET");
// read the response
InputStream in = new BufferedInputStream(conn.getInputStream());
response = convertStreamToString(in);
} catch (MalformedURLException e) {
Log.e(TAG, "MalformedURLException: " + e.getMessage());
} catch (ProtocolException e) {
Log.e(TAG, "ProtocolException: " + e.getMessage());
} catch (IOException e) {
Log.e(TAG, "IOException: " + e.getMessage());
} catch (Exception e) {
Log.e(TAG, "Exception: " + e.getMessage());
}
return response;
}
private String convertStreamToString(InputStream is) {
BufferedReader reader = new BufferedReader(new InputStreamReader(is));
StringBuilder sb = new StringBuilder();
String line;
try {
while ((line = reader.readLine()) != null) {
sb.append(line).append('\n');
}
} catch (IOException e) {
e.printStackTrace();
} finally {
try
{
is.close();
}
catch (IOException e) {
e.printStackTrace();
}
}
return sb.toString();
}
}
public class API_Test_1_1 extends AppCompatActivity {
private String TAG = API_Test2.class.getSimpleName();
private ListView lv;
ArrayList<HashMap<String, String>> contactList;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.api_test_1_1);
contactList = new ArrayList<>();
lv = (ListView) findViewById(R.id.list);
new API_Test_1_1.GetContacts().execute();
}
private class GetContacts extends AsyncTask<Void, Void, Void> {
@Override
protected void onPreExecute() {
super.onPreExecute();
Toast.makeText(API_Test_1_1.this,"Json Data is downloading",Toast.LENGTH_LONG).show();
}
@Override
protected Void doInBackground(Void... arg0) {
API_HttpHandler_1_1 sh = new API_HttpHandler_1_1();
// Making a request to url and getting response
String url = "http://klmop2-001-site1.gtempurl.com/api/Students";
String jsonStr = sh.makeServiceCall(url);
Log.e(TAG, "Response from url: " + jsonStr);
if (jsonStr != null) {
try {
//JSONObject jsonObj = new JSONObject(jsonStr);
JSONObject jsonObj = new JSONObject(jsonStr);
// Getting JSON Array node
JSONArray contacts = jsonObj.getJSONArray("Students");
// looping through All Contacts
for (int i = 0; i < contacts.length(); i++) {
JSONObject c = contacts.getJSONObject(i);
//JSONArray c = contacts.getJSONArray(i);
String id = c.getString("ID");
String name = c.getString("Name");
String roll = c.getString("Roll");
// tmp hash map for single contact
HashMap<String, String> contact = new HashMap<>();
// adding each child node to HashMap key => value
contact.put("ID", id);
contact.put("Name", name);
contact.put("Roll", roll);
// adding contact to contact list
contactList.add(contact);
}
}
catch (final JSONException e) {
Log.e(TAG, "Json parsing error: " + e.getMessage());
runOnUiThread(new Runnable() {
@Override
public void run() {
Toast.makeText(getApplicationContext(),
"Json parsing error: " + e.getMessage(),
Toast.LENGTH_LONG).show();
}
});
}
} else {
Log.e(TAG, "Couldn't get json from server.");
runOnUiThread(new Runnable() {
@Override
public void run() {
Toast.makeText(getApplicationContext(),
"Couldn't get json from server. Check LogCat for possible errors!",
Toast.LENGTH_LONG).show();
}
});
}
return null;
}
@Override
protected void onPostExecute(Void result) {
super.onPostExecute(result);
ListAdapter adapter = new SimpleAdapter(API_Test_1_1.this, contactList,
R.layout.api_list_item_1_1, new String[]{ "Name","Roll"},
new int[]{R.id.Name, R.id.Roll});
lv.setAdapter(adapter);
}
}
}
解决方案
推荐阅读
- html - 在我的网站上堆叠对象和截止
- python - zipfile.BadZipFile:将 excel 行导出为文本时文件不是 zip 文件
- python-3.x - 如何同时为多个按钮分配一个功能?Python
- python - Python 中的年份计数
- jenkins - Jenkins - 内存中的 git Checkout
- python - 如何获得字典中最大的n个值但保持位置
- python - 将特定值 x 次复制到新列中
- docker - 在 Docker build 中修改 /etc/hosts
- css - CSS textOverflow:'省略号'不起作用?
- java - 当堆栈帧中的对象引用变量分配一个新值时,它究竟会发生什么?