spacy - Spacy NLP 示例：无法将标记转换为小写，抛出错误

Question

from collections import defaultdict
item_ratings = defaultdict(list)

for idx, review in data.iterrows():

    doc = nlp(review.text)

    matches = matcher(doc)
    
    found_items = set(doc[match[1]:match[2]].lower_ for match in matches)

    
for item in found_items:
        
    item_ratings[item].append(review.stars)

错误：

AttributeError: 'spacy.tokens.span.Span' object has no attribute 'lower_'

我需要标记为小写，我该怎么做？

标签： spacyspacy-3

Answer 1

found_items = set(doc[match[1]:match[2]].text.lower() for match in matches)

就像错误所说的那样，Span对象没有lower_. 您可以使用textthen that' 只是一个字符串，以便您可以将其小写。