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ruby - Ruby - 我希望代码只在特定条件下工作，但不知道该怎么做

问题描述

我知道我一定遗漏了一些东西，arr2.each_index但我想不出还有什么可以添加的......我的大脑正在融化大声笑下面的代码应该只在 arr2 中没有大于 num 的“num”时执行，但是现在只要 arr2 中有一个大于 num 的“num”，它们就会执行。我希望这个问题是有道理的。

arr = [{"num":1,"head":5},{"num":3,"head":1},{"num":4,"head":1},{"num":5,"head":7}]
arr2 = [{"init1":[{"num":2,"head":1}]},{"init2":[{"num":35,"head":2}]},{"init3":[{"num":98,"head":1}]},{"init4":[{"num":51,"head":1},{"num":77,"head":5}]}]
arr3 = []

puts "Card you want to place outside? "
num = gets.chomp.to_i

def add_card_to_init(arr, arr2, arr3, num)  
  arr.each_with_index do |card, index|
    if card[:num] == num
        catch :skip do
            arr2.each_index do |index|
                x = arr2[index].values[0]
                if num > x[x.length-1][:num]
                  #code
                  puts "num > init"
                else
                  # code only runs when no num > x[x.length-1][:num] 
                  puts "num < init"
                  throw :skip
                end
            end
        end
    end
  end
end

add_card_to_init(arr, arr2, arr3, num)

当 num = 3 时期望输出

num > init

但我得到的是

num > init
num < init

提前致谢！

标签： rubyloops

解决方案

the easiest way would be to set a flag "smaller" to true before you enter the each_index loop and set it to false inside the loop if init >= num. And then run your code outside the loop based on the flag. That's not elegant but quick and dirty. Optionally you can leave the loop on the first false event.

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