discord.py - 如何摆脱keep_alive的错误？

Question

from keep_alive import keep_alive

有错误

导入“keep_alive”无法解决

同一个目录，有保持活动文件有人帮助我吗？基本上怎么活

标签： discord.py

Answer 1

from flask import Flask

from threading import Thread

app = Flask('')


app.route('/')

def main():
  return "Bot is online."


def run():
  app.run(host = "0.0.0.0", port = 8000)


def keep_alive():
  server = Thread(target = run)
  server.start()

这就是 keep_alive 文件包含的内容，并将其命名为 host.py 之类的。如果您将其命名为 host.py，那么您也应该在 main.py 中添加它。

from host import keep_alive
keep_alive() #added at the bottom after all commands