python - 重玩功能仅在用户输掉游戏时才起作用（刽子手）

问题描述

因此，在用户赢或输后，他们会被询问是否要再次玩（Y/N）。

这里应该发生 3 件事：

他们输入 Y 并开始新游戏。

他们键入 N，游戏结束。

他们输入不同的字符，在这种情况下他们会收到消息：请输入有效的答案。(Y/N)，他们被问到是否想再玩一次

当用户输了并且他们被要求再次玩时，上述所有三个标准都有效。但是，当用户获胜并被要求再次玩时，只有无效字符消息有效。当他们输入 Y 时，他们会进入一个新游戏，除了你已经猜到的字母不会重置 + 一次猜测后，单词会立即显示并且他们再次“获胜”（你“猜猜”也不要“ t 重置）。当他们输入 N 时，游戏继续。

以下是问题的图片： https ://imgur.com/gallery/PWiSTWP

我完全不知道发生了什么，因为我为每个场景使用了相同的代码（用户获胜或用户失败）：

        playagain = input('Wanna play again? (Y/N) ').upper()
        if playagain == 'Y':
            word = random.choice(wordbank)
        elif playagain == 'N':
            print('Alright, goodbye.')
        while playagain != 'Y' and playagain != 'N':
            print('Please type a valid answer. (Y/N)')
            print()
            playagain = input('Wanna play again? (Y/N) ').upper()

这是我的整个游戏代码：

# importing wordbank
import random
from wordbankcool import wordbank

# hangman graphics
hangman_graphics = ['_',
                    '__',
                    '__\n |',
                    '__\n |\n O',
                    '__\n |\n O\n |',
                    '__\n |\n O\n/|',
                    '__\n |\n O\n/|\ ',
                    '__\n |\n O\n/|\ \n/',
                    '__\n |\n O\n/|\ \n/ \ '
                    ]

# code is inside while loop
playagain = 'Y'
while playagain == 'Y':

    # alphabet
    alphabet = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l',
                'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']

    # basic functions of the game
    mistakes = 0
    letters_guessed = []
    mistakes_allowed = len(hangman_graphics)

    # selecting a random word for the user to guess
    word = random.choice(wordbank)

    # letters user has guessed stored in list, making each letter of the word seperate
    letters_word = list(word)
    wrong_letters = []

    print()

    # amount of letters the word has
    print(f'The word has {len(letters_word)} letters')

    # while loop which will run until the the number of mistakes = number of mistakes allowed
    while mistakes < mistakes_allowed:
        print()
        print('Incorrect guesses: ', end='')
        for letter in wrong_letters:
            print(f'{letter}, ', end='')
        print()
        print(f'Guesses left: {mistakes_allowed - mistakes}')
        letter_user = input('Guess a letter: ').lower()

    # checking if the letter has been guessed before
        while letter_user in letters_guessed or letter_user in wrong_letters:
            print()
            print('You have already guessed this letter. Please guess a different one.')
            letter_user = input('Guess a letter: ')

    # increasing amount of mistakes if the letter that has been guessed is not in the word + checking if guess is a letter
        if letter_user not in alphabet:
            print('Please only enter A LETTER.')
            continue
        if letter_user not in letters_word:
            mistakes += 1
            wrong_letters.append(letter_user)

        print()

        # showing how many letters the user has/has not guessed
        print('Word: ', end='')

    # if letter is in word, its added to letters guessed
        for letter in letters_word:
            if letter_user == letter:
                letters_guessed.append(letter_user)

    # replace letters that haven't been guessed with an underscore
        for letter in letters_word:
            if letter in letters_guessed:
                print(letter + ' ', end='')
            else:
                print('_ ', end='')

        print()

    # hangman graphics correlate with amount of mistakes made
        if mistakes:
            print(hangman_graphics[mistakes - 1])
        print()
        print('-------------------------------------------')  # seperator

    # ending: user wins
        if len(letters_guessed) == len(letters_word):
            print()
            print(f'You won! The word was {word}!')
            print()
            playagain = input('Wanna play again? (Y/N) ').upper()
            if playagain == 'Y':
                word = random.choice(wordbank)
            elif playagain == 'N':
                print('Alright, goodbye.')
            while playagain != 'Y' and playagain != 'N':
                print('Please type a valid answer. (Y/N)')
                print()
                playagain = input('Wanna play again? (Y/N) ').upper()

    # ending: user loses
    if mistakes == mistakes_allowed:
        print()
        print('Unlucky, better luck next time.')
        print()
        print(f'The word was {word}.')
        print()
        playagain = input('Wanna play again? (Y/N) ').upper()
        if playagain == 'Y':
            word = random.choice(wordbank)
        elif playagain == 'N':
            print('Alright, goodbye.')
        while playagain != 'Y' and playagain != 'N':
            print('Please type a valid answer. (Y/N)')
            print()
            playagain = input('Wanna play again? (Y/N) ').upper()

标签： python

python - 重玩功能仅在用户输掉游戏时才起作用（刽子手）

问题描述

解决方案

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