首页 > 解决方案 > 为什么 ucontext_t 执行后不返回 un_lick?

问题描述

我正在尝试实现一个协程,但是在我的代码中,我指定ctx_main了 for uc_lick,但是在执行完routine2对应的子程序后ucontext_t,程序直接退出而不是返回main函数继续执行。

我已经阅读了linux手册。按照我的理解,应该可以main在子程序执行后返回函数,但目前只routine1在执行后返回main,程序执行后直接退出routine2

而退出状态码是routine2(19,的返回值printf)中最后一个函数的返回值。为什么会这样?

#include <stdio.h>
#include <ucontext.h>

typedef void (*coroutine_func)();

#define STACK_SIZE (1<<15)

ucontext_t ctx_main;
ucontext_t c1, c2;

ucontext_t create_ctx(coroutine_func func, ucontext_t *ret_ctx) {
    ucontext_t ctx;

    getcontext(&ctx);

    char stack[STACK_SIZE];
    ctx.uc_stack.ss_sp = stack;
    ctx.uc_stack.ss_size = sizeof(stack);

    ctx.uc_link = ret_ctx;

    makecontext(&ctx, func, 0);

    return ctx;
}

void routine1() {
    printf("routine1 running\n");
    swapcontext(&c1, &c2);
    printf("routine1 returning\n");
}


void routine2() {
    printf("routine2 running\n");
    swapcontext(&c2, &c1);
    printf("routine2 returning\n"); // return value is 19
}

int main() {
    c1 = create_ctx(routine1, &ctx_main);
    c2 = create_ctx(routine2, &ctx_main);

    swapcontext(&ctx_main, &c1);
    swapcontext(&ctx_main, &c2);

    // Will not run to here, exit after routine2 is executed.
    printf("main exiting.\n");

    return 0;
}

结果:

routine1 running
routine2 running
routine1 returning
routine2 returning

Process finished with exit code 19

标签: c

解决方案


您在变量停止存在后使用它。

ucontext_t create_ctx(coroutine_func func, ucontext_t *ret_ctx) {
    char stack[STACK_SIZE]; // allocated on stack
    ctx.uc_stack.ss_sp = stack;
    return ctx; // ss_sp is invalid pointer
}               // variable stack stops existing

您必须分配具有足够生命周期的内存。例如:

char *stack = malloc(STACK_SIZE);
ctx.uc_stack.ss_sp = stack;
ctx.uc_stack.ss_size = STACK_SIZE;

如何检查:使用 sanitizer 选项进行编译,它们将帮助您调试程序:

+ gcc -D_FORTIFY_SOURCE=2 -D_GLIBCXX_ASSERTIONS -fstack-clash-protection -fstack-protector-all -fstack-protector-strong -ggdb3 -grecord-gcc-switches -fcf-protection -O -Wall -Wextra -Wwrite-strings -Wno-unused-function -Wno-unused-parameter -Wno-implicit-function-declaration -fsanitize=address,undefined,pointer-compare,pointer-subtract /tmp/1.c
==1265711==WARNING: ASan doesn't fully support makecontext/swapcontext functions and may produce false positives in some cases!
routine1 running
routine2 running
routine2 returning
*** stack smashing detected ***: terminated

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