html - JSON输出与Node JS一团糟
问题描述
我用 Node JS 创建了一个简单的网络爬虫来提取手表价格,下面是代码:
import axios from 'axios'
import cheerio from 'cheerio'
import * as fs from 'fs'
let Array1=[];
let a = 0;
let b=1;
axios.get("URL").then((response) => {
let $ = cheerio.load(response.data);
$(".article-title").each((i, e) => {
let title = $(e).text();
Array1[a] = title;
a = a+2;
}
)
$(".article-price").each((i, e) => {
let price = $(e).text();
Array1[b] = price;
b = b+2;
}
)
let data = JSON.stringify(Array1);
fs.writeFileSync('sub.json', data);
});
但是,JSON 输出如下:
["\n Rolex Submariner 5513 Maxi MK5 Dial","\n \n \n 16 000 €\n ","\n Rolex Submariner Black Dial Date 41mm - 2021 - 126610LN","\n \n \n 14 839 €\n ","\n Rolex Black Dial Submariner Date 41mm - 2021 Card - 126610ln","\n \n \n 14 839 €\n ","\n Rolex Submariner Meter First MK1","\n \n \n 15 416 €\n ","\n Rolex Submariner 16610 military NATO 1994 S series","\n \n \n 35 000 €\n ","\n Rolex Submariner 126610LV Starbucks NEW 06/2021 Full set","\n \n \n 17 400 €\n ","\n Rolex 06/2021 - Submariner Date 126610 LN 99%new","\n \n \n 13 300 €\n ","\n Rolex Submariner 6536 Gilt James Bond 1956","\n \n \n 33 000 €\n ","\n Rolex Submariner Date Starbucks Automatik Edelstahl Herrenuhr...","\n \n \n 17 770 €\n ","\n Rolex Submariner","\n \n \n 12 500 €\n ","\n Rolex Submariner Date NOS avec stickers","\n \n \n 17 900 €\n ","\n Rolex Submariner 5513 \"Meter first\"","\n \n \n 16 000 €\n ","\n Rolex Submariner","\n \n \n 9 700 €\n ","\n Rolex Submariner 16610LV Kermit Y series 2003 Fat Four Mark 1...","\n \n \n 38 000 €\n ","\n Rolex Submariner Date 116610LN Boite/Papiers 2020","\n \n \n 13 790 €\n ","\n Rolex NEW 2021 some stickers - Submariner No Date 124060","\n \n \n 12 490 €\n ","\n Rolex Submariner 14060M Full Set","\n \n \n 10 900 €\n ","\n Rolex Submariner Date 18K Gold Automatik Herrenuhr Oyster...","\n \n \n 27 240 €\n ","\n Rolex \"Submariner \"\"Hulk\"\"\"Model 116610LV Full Set 2017","\n \n \n 19 950 €\n ","\n Rolex Submariner Date 116619LB Rolex Serviced 2017","\n \n \n 36 500 €\n ","\n Rolex Submariner 5513 Feet First","\n \n \n 16 000 €\n ","\n Rolex Submariner","\n \n \n 12 900 €\n ","\n Rolex Submariner 5513 Maxi dial 1979","\n \n \n 19 000 €\n ","\n Rolex Submariner Date 16610 Boite / Papiers","\n \n \n 11 750 €\n ","\n Rolex Mint 2021 KERMIT / STARBUCKS - Submariner Date 126610 LV...","\n \n \n 17 500 €\n ","\n Rolex Submariner 41 No-Date - 124060 - Full Set - 2021","\n \n \n 12 900 €\n ","\n Rolex Submariner Date Stahl / Gold Automatik Herrenuhr Oyster...","\n \n \n 9 550 €\n ","\n Rolex Submariner (No Date) 14060M 2 Lines Full set 2005","\n \n \n 11 200 €\n ","\n Rolex Submariner Date 41mm NEW 09/2021","\n \n \n 14 500 €\n ","\n Rolex Submariner 16610LV \"Kermit\"","\n \n \n 17 500 €\n ","\n Rolex Submariner Céramique 40mm","\n \n \n 12 900 €\n ","\n Rolex Submariner 5513 Gilt Glossy 1966 Rolex warranty","\n \n \n 48 000 €\n ","\n Rolex Submariner 14060M Boite / Papiers","\n \n \n 11 450 €\n ","\n Rolex Submariner date - Oyster Perpetual","\n \n \n 18 000 €\n ","\n Rolex Submariner Date - 116610LN- Full Set - 2012","\n \n \n 12 500 €\n ","\n Rolex Submariner No Date Automatik Stahl Oyster Perpetual Ref....","\n \n \n 10 650 €\n ","\n Rolex Submariner 116610 \"Hulk\" 2010 SERIE G FULL SET STICKERS","\n \n \n 22 500 €\n ","\n Rolex Submariner Date Or Blanc 41mm New 07/2021","\n \n \n 43 900 €\n ","\n Rolex Submariner Date 2000 Full set","\n \n \n 10 800 €\n ","\n Rolex Submariner","\n \n \n 11 900 €\n ","\n Rolex Submariner 16610 COMEX M series full set 2008","\n \n \n 89 000 €\n ","\n Rolex Submariner Date Purple dial","\n \n \n 12 290 €\n ","\n Rolex Submariner (No Date)","\n \n \n 11 000 €\n ","\n Rolex Submariner 5508 Tropical James Bond - 1958","\n \n \n 26 000 €\n ","\n Rolex Submariner Date Kermit Automatik Stahl Herrenuhr Ref....","\n \n \n 16 950 €\n ","\n Rolex montre rolex 5513 submariner 39 mm automatique en acier...","\n \n \n 11 120 €\n ","\n Rolex Submariner \"Kermit\"1661OLV","\n \n \n 17 000 €\n ","\n Rolex Submariner Date 1996 série W Full set","\n \n \n 10 900 €\n ","\n Rolex Submariner","\n \n \n 11 900 €\n ","\n Rolex Submariner 16610 S series 1994 tritium from Hawaii","\n \n \n 14 900 €\n ","\n Rolex Submariner Date Mk1 military NATO rare country code 905...","\n \n \n 13 290 €\n ","\n Rolex Submariner Date","\n \n \n 15 000 €\n ","\n Rolex Submariner 5513","\n \n \n 12 500 €\n ","\n Rolex Submariner Date Stahl / Gold Automatik Oyster Perpetual...","\n \n \n 14 250 €\n ","\n Rolex submariner 16613t 40 mm automatique or & acier gold new...","\n \n \n 12 845 €\n ","\n Rolex Submariner Date de 1988","\n \n \n 8 900 €\n ","\n Rolex Submariner No Date 14060 4 Lignes 2009 Full Set","\n \n \n 12 000 €\n ","\n Rolex Submariner \"Kermit\"","\n \n \n 17 000 €\n ","\n Rolex Submariner","\n \n \n 9 600 €\n ","\n Rolex Submariner Date 116613 LN","\n \n \n 13 500 €\n ","\n Rolex Submariner Date Blue Dial 40mm Gold steel FULL SET","\n \n \n 12 980 €\n ","\n Rolex Submariner No Date Stickers - 124060 - Full Set - 2020","\n \n \n 12 500 €\n ","\n Rolex Submariner Stahl / Gold Automatik Herrenuhr Ref....","\n \n \n 16 020 €\n ","\n Rolex Submariner Date","\n \n \n 11 150 €\n "]
为了使用 jQuery 获取数据并在 HTML 表中显示,我怎样才能使它变得更好?我想要一个如下所示的 JSON 输出:
[
{
"title": "Rolex Submariner 5513 Maxi MK5 Dial",
"price": "16 000"
},
{
"title": "Rolex Submariner Black Dial Date 41mm - 2021 - 126610LN",
"price": "14 839"
},
非常感谢!!卡在这里好几天了...
解决方案
Array1.push({title: $(e).text()});
Array1.push({price: $(e).text()});
您应该将键及其值放入对象中,然后将其放入数组中。您将值放入 title 变量中,然后将其传递给数组,以便将其替换为它们的值而不是单词:“title”等等...
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