mysql - 在 JPA 中找不到实体实体类实例变量的属性
问题描述
我创建了一个患者实体类并将患者 ID 实例变量声明为主键。我在需要的地方使用每个 patientId ,但在我使用的地方没有 patientid 。当我运行我的应用程序时,我在运行时遇到此类错误。我正确检查了我的应用程序但我无法找到我的错误
Caused by: org.springframework.data.mapping.PropertyReferenceException: No property patientid found for type Patient! Did you mean 'patientId'?
at org.springframework.data.mapping.PropertyPath.<init>(PropertyPath.java:90) ~[spring-data-commons-2.5.5.jar:2.5.5]
at org.springframework.data.mapping.PropertyPath.create(PropertyPath.java:437) ~[spring-data-commons-2.5.5.jar:2.5.5]
at org.springframework.data.mapping.PropertyPath.create(PropertyPath.java:413) ~[spring-data-commons-2.5.5.jar:2.5.5]
at org.springframework.data.mapping.PropertyPath.lambda$from$0(PropertyPath.java:366) ~[spring-data-commons-2.5.5.jar:2.5.5]
at java.base/java.util.concurrent.ConcurrentMap.computeIfAbsent(ConcurrentMap.java:330) ~[na:na]
at org.springframework.data.mapping.PropertyPath.from(PropertyPath.java:348) ~[spring-data-commons-2.5.5.jar:2.5.5]
at org.springframework.data.mapping.PropertyPath.from(PropertyPath.java:331) ~[spring-data-commons-2.5.5.jar:2.5.5]
at org.springframework.data.repository.query.parser.OrderBySource.lambda$createOrder$2(OrderBySource.java:112) ~[spring-data-commons-2.5.5.jar:2.5.5]
at java.base/java.util.Optional.map(Optional.java:260) ~[na:na]
at org.springframework.data.repository.query.parser.OrderBySource.createOrder(OrderBySource.java:110) ~[spring-data-commons-2.5.5.jar:2.5.5]
at org.springframework.data.repository.query.parser.OrderBySource.<init>(OrderBySource.java:94) ~[spring-data-commons-2.5.5.jar:2.5.5]
at org.springframework.data.repository.query.parser.PartTree$Predicate.<init>(PartTree.java:386) ~[spring-data-commons-2.5.5.jar:2.5.5]
at org.springframework.data.repository.query.parser.PartTree.<init>(PartTree.java:95) ~[spring-data-commons-2.5.5.jar:2.5.5]
at org.springframework.data.jpa.repository.query.PartTreeJpaQuery.<init>(PartTreeJpaQuery.java:89) ~[spring-data-jpa-2.5.5.jar:2.5.5]
... 70 common frames omitted
病人.kt
package com.nillmani.hospitalmanagement.entity
import com.nillmani.hospitalmanagement.entity.enum.City
import java.time.LocalDate
import javax.persistence.*
@Entity
data class Patient(
@Id
@GeneratedValue(strategy = GenerationType.SEQUENCE,generator = "AA_PATIENT_SEQ")
@SequenceGenerator(sequenceName = "AA_PATIENT_SEQ" , allocationSize = 1,name = "AA_PATIENT_SEQ")
var patientId:Long=-1,
val name :String="",
val lastName: String="",
val phoneNumber :String="",
val dateOfBirth : LocalDate= LocalDate.now(),
val gender : String="",
@Enumerated(EnumType.ORDINAL)
val city: City,
@Column(unique = true)
val email:String="",
var status:Int=0,
@OneToMany(cascade = [CascadeType.ALL], fetch = FetchType.LAZY,mappedBy ="patient" )
val disease: MutableList<Disease> = ArrayList(),
@OneToMany(cascade = [CascadeType.ALL], fetch = FetchType.LAZY,mappedBy = "patient")
val admission : List<Admissions> = ArrayList()
)
PatientJpaRepository.kt
package com.nillmani.hospitalmanagement.repository
import com.nillmani.hospitalmanagement.entity.Patient
import org.springframework.data.jpa.repository.JpaRepository
import org.springframework.data.jpa.repository.Query
import java.util.*
interface PatientRepository :JpaRepository<Patient,Long> {
@Query("select p from Patient p where p.status = 1 order by p.patientId ASC")
fun findAllByStatusEquelsOne(): List<Patient?>?
}
病人服务.kt
/**Update the patient disease details*/
@Throws(Exception::class)
fun updatePatientDisease(patientId: Long,patient: Patient):Boolean{
val seekPerson : Optional<Patient> = patientRepository.findById(patientId)
if (seekPerson.isPresent){
patient.patientId = patientId
patientRepository.save(patient)
return true
}else{
logger.error("patient does not with this id $patientId")
throw PatientNotFoundException()
}
}
病人控制者.kt
@DeleteMapping("/{patientId}")
@Throws(Exception::class)
fun deletePatient(@PathVariable(name = "patientId", required = true) patientId: Long): ResponseEntity<Boolean?>? {
return ResponseEntity.ok(patientService.delete(patientId))
}
解决方案
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