python - 如何仅通过 int 对字符串和 int 值的字典进行排序

Question

例如从字典

{"Name": "Mark","country": "England", "Age":15,

"Name": "Tom","country": "Poland", "Age":10,

"Name": "Sam","country": "USA", "Age":19,

"Name": "Bob","country": "Italy", "Age":17}

我想得到

{"Name": "Tom","country": "Poland", "Age":10,

"Name": "Mark","country": "England", "Age":15,

"Name": "Bob","country": "Italy", "Age":17,

"Name": "Sam","country": "USA", "Age":19,}

像这样的代码没有帮助

for key, value in sorted(dict.items(), key=lambda item: int(item[0]))

标签： pythonsortingdictionary

Answer 1

假设你打算有一个这样的字典列表：

a = [{"Name": "Tom","country": "Poland", "Age":10},
     {"Name": "Mark","country": "England", "Age":15},
     {"Name": "Bob","country": "Italy", "Age":17},
     {"Name": "Sam","country": "USA", "Age":19}]

这个数据集最明显的答案是：

sorted(a, key=lambda x:x["Age"])

对于对所有整数值进行排序的更一般情况，您可以使用以下内容：

sorted(a, key=lambda x: sum(v for v in x.values() if isinstance(v, int)))

尽管根据您的用例检查int可能过于狭窄的标准。该解决方案首先对 dict 中的所有整数求和(v for v in x.values() if isinstance(v, int))，然后对该总和进行排序。