python - Python Scipy fsolve函数返回等于起点的根
问题描述
我需要得到一个标量方程的所有根。但是 fsolve 每次调用只能返回 1 个根。所以我设计了一个fsolve的自调用功能find_root_recursively
。此函数将调用自身,直到新根等于前一个根,这意味着fsovle
已找到所有根,不会再添加新根。我使用这个逻辑来结束自我调用。但在某些情况下fsolve
会返回一个与起点完全相同的根。one_root
=start
总是。显然这start
不是根。所以list_root
总是在添加新的根,它永远不会结束。
min_value = df_group['strike'].min()
start_point = int(float(min_value) * 0.8)
def find_root_by_small_step(function, start_0, increment):
start = start_0
one_root = fsolve(function, start)
def get_transaction_data(self, expiry_date, df_group):
return df_group[df_group['expiration_date'] == expiry_date].loc[(df_group['type'] == 1) & (df_group['position'] == 1)], \
df_group[df_group['expiration_date'] == expiry_date].loc[(df_group['type'] == 1) & (df_group['position'] == 0)], \
df_group[df_group['expiration_date'] == expiry_date].loc[(df_group['type'] == 0) & (df_group['position'] == 1)], \
df_group[df_group['expiration_date'] == expiry_date].loc[(df_group['type'] == 0) & (df_group['position'] == 0)]
def calculate_one_payoff(self, stock_price, df_long_call, df_short_call, df_long_put, df_short_put):
# buy call
df_buy_call_executed = df_long_call[stock_price >= df_long_call['strike']]
if len(df_buy_call_executed) > 0:
buy_call_executed_sum = ((stock_price - df_buy_call_executed['breakeven_price']) * df_buy_call_executed['option_amount']).sum()
else:
buy_call_executed_sum = 0
df_buy_call_noExec = df_long_call[stock_price < df_long_call['strike']]
if len(df_buy_call_noExec) > 0:
buy_call_noExec_sum = (-1 * df_buy_call_noExec['option_price'] * df_buy_call_noExec['option_amount']).sum()
else:
buy_call_noExec_sum = 0
# sell call
df_sell_call_executed = df_short_call[stock_price >= df_short_call['strike']]
if len(df_sell_call_executed) > 0:
sell_call_executed_sum = ((df_sell_call_executed['breakeven_price'] - stock_price) * df_sell_call_executed['option_amount']).sum()
else:
sell_call_executed_sum = 0
df_sell_call_noExec = df_short_call[stock_price < df_short_call['strike']]
if len(df_sell_call_noExec) > 0:
sell_call_noExec_sum = (df_sell_call_noExec['option_price'] * df_sell_call_noExec['option_amount']).sum()
else:
sell_call_noExec_sum = 0
# buy put
df_buy_put_executed = df_long_put[stock_price < df_long_put['strike']]
if len(df_buy_put_executed) > 0:
buy_put_executed_sum = ((df_buy_put_executed['breakeven_price'] - stock_price) * df_buy_put_executed['option_amount']).sum()
else:
buy_put_executed_sum = 0
df_buy_put_noExec = df_long_put[stock_price >= df_long_put['strike']]
if len(df_buy_put_noExec) > 0:
buy_put_noExec_sum = (-1 * df_buy_put_noExec['option_price'] * df_buy_put_noExec['option_amount']).sum()
else:
buy_put_noExec_sum = 0
# sell put
df_sell_put_executed = df_short_put[stock_price < df_short_put['strike']]
if len(df_sell_put_executed) > 0:
sell_put_executed_sum = ((stock_price - df_sell_put_executed['breakeven_price']) * df_sell_put_executed['option_amount']).sum()
else:
sell_put_executed_sum = 0
df_sell_put_noExec = df_short_put[stock_price >= df_short_put['strike']]
if len(df_sell_put_noExec) > 0:
sell_put_noExec_sum = (df_sell_put_noExec['option_price'] * df_sell_put_noExec['option_amount']).sum()
else:
sell_put_noExec_sum = 0
one_stock_price_sum = buy_call_executed_sum + buy_call_noExec_sum + sell_call_executed_sum + sell_call_noExec_sum + \
buy_put_executed_sum + buy_put_noExec_sum + sell_put_executed_sum + sell_put_noExec_sum
one_stock_price_sum = float(one_stock_price_sum)
return one_stock_price_sum
df_long_call, df_short_call, df_long_put, df_short_put = self.get_transaction_data(expiry_date, df_group)
find_root_by_small_step(function=calculate_one_payoff, start=start_point, increment=increment)
ticker type position expiration_date strike option_price option_amount breakeven_price
AAPL 1 0 2021-11-19 145.0000 5.1700 2500.0000 150.1700
AAPL 0 1 2021-11-19 145.0000 2.9700 2500.0000 142.0300
AAPL 0 1 2021-11-19 145.0000 2.7000 5000.0000 142.3000
AAPL 1 1 2021-11-19 145.0000 5.8500 5000.0000 150.8500
AAPL 1 1 2021-11-19 155.0000 1.6000 1050.0000 156.6000
True root = 139.9 and 159.0
解决方案
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