首页 > 解决方案 > 在 Pygame 中用图像替换矩形

问题描述

一般来说,我是 pygame 和 python 的新手。今天我试图编写一个简化的 TopDown 运动。我做到了,它运行没有任何问题。但无论如何我有一个问题:“玩家”是一个矩形,但我希望他是一个图像或类似的东西。有没有办法将矩形“转换”为图像?

哦,如果你需要,这里是代码,我是从一周前(或更长一点)问的另一个问题中得到的:

import pygame

pygame.init()

win = pygame.display.set_mode((700, 700))
pygame.display.set_caption("TopDown")
clock = pygame.time.Clock()

player = pygame.Rect(350, 350, 40, 60)
vel = 1

run = True
while run:
    clock.tick(50)

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            run = False

    keys = pygame.key.get_pressed()
    player.x += (keys[pygame.K_d] - keys[pygame.K_a]) * vel
    player.y += (keys[pygame.K_s] - keys[pygame.K_w]) * vel
            
    win.fill((0, 0, 0))
    pygame.draw.rect(win, (255, 255, 255), player)
    pygame.display.update()

pygame.quit()

标签: pythonpygame

解决方案


加载图像pygame.image.load()。此函数返回一个pygame.Surface对象:

player_image = pygame.image.load("player_image.png").convert_alpha()
player_rect = player_image.get_rect(center = (350, 350))

Surface放到显示器上pygame.Surface.blit

win.blit(player_image, player_rect)

最小的例子:

import pygame
pygame.init()

win = pygame.display.set_mode((700, 700))
pygame.display.set_caption("TopDown")
clock = pygame.time.Clock()

player_image = pygame.image.load("player_image.png").convert_alpha()
player_rect = player_image.get_rect(center = (350, 350))
vel = 5

run = True
while run:
    clock.tick(50)

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            run = False

    keys = pygame.key.get_pressed()
    player_rect.x += (keys[pygame.K_d] - keys[pygame.K_a]) * vel
    player_rect.y += (keys[pygame.K_s] - keys[pygame.K_w]) * vel
            
    win.fill((64, 238, 255))
    win.blit(player_image, player_rect)
    pygame.display.update()

pygame.quit()

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