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java - 如何杰克逊序列化/反序列化物料清单实体

问题描述

我的数据库有许多物料清单结构，包括定义各方之间关系的结构：

政党关系逻辑模型

第一个互动者倾向于扮演高级角色——例如雇主——而第二个互动者倾向于扮演次要角色——例如雇员。

我希望能够将其序列化为 JSON，但我遇到了问题。

我的实体注释如下：

聚会

@OneToMany(
    targetEntity = PartyRelationshipDO.class,
    fetch = FetchType.LAZY, cascade = CascadeType.ALL
)
@JoinColumn(name = "first_party_id", referencedColumnName = "party_id")
@JsonProperty("firstParties")
@JsonManagedReference(value = "FirstParty")
private Set<PartyRelationshipDO> firstParties;

@OneToMany(
    targetEntity = PartyRelationshipDO.class,
    fetch = FetchType.LAZY, cascade = CascadeType.ALL
)
@JoinColumn(name = "second_party_id", referencedColumnName = "party_id")
@JsonProperty("secondParties")
@JsonManagedReference(value = "SecondParty")
private Set<PartyRelationshipDO> secondParties;

当事人关系

@ManyToOne(optional = false)
@JoinColumn(name = "first_party_id", referencedColumnName = "party_id")
@JsonProperty("firstParty")
@JsonBackReference(value = "FirstParty")
private PartyDO firstParty;

@ManyToOne(optional = false)
@JoinColumn(name = "second_party_id", referencedColumnName = "party_id")
@JsonProperty("secondParty")
@JsonBackReference(value = "SecondParty")
private PartyDO secondParty;

这在一定程度上起作用。当我序列化我的测试用例时，我得到：

{
    "partyId": 1,
    "partyIdentifier": "first.interactor@email.address",
    "isDeleted": false,
    "partyIdentifierType": {
        "typeKey": "EMAIL_ADDRESS"
    },
    "secondParties": [
        {
            "effectivePeriodFrom": "2021-11-01T15:55:38.518Z",
            "isDeleted": false,
            "firstPartyId": 1,
            "secondPartyId": 2
        }
    ],
    "firstName": "First",
    "lastName": "Interactor"
}

问题是，secondParty对象没有在"secondParties"数组中序列化。我想看到的是：

{
    "partyId": 1,
    "partyIdentifier": "first.interactor@email.address",
    "isDeleted": false,
    "partyIdentifierType": {
        "typeKey": "EMAIL_ADDRESS"
    },
    "secondParties": [
        {
            "effectivePeriodFrom": "2021-11-01T15:55:38.518Z",
            "isDeleted": false,
            "firstPartyId": 1,
            "secondPartyId": 2,
            "secondParty": {
                "partyId": 2,
                "partyIdentifier": "second.interactor@email.address",
                "isDeleted": false,
                "partyIdentifierType": {
                    "typeKey": "EMAIL_ADDRESS"
                },
                "firstName": "Second",
                "lastName": "Interactor"
            }
        }
    ],
    "firstName": "First",
    "lastName": "Interactor"
}

如果我不使用@JsonManagedReferenceand @JsonBackReference，我会得到一个StackOverflowError重复的堆栈跟踪块：

at com.fasterxml.jackson.databind.ser.std.CollectionSerializer.serialize(CollectionSerializer.java:25)
at com.fasterxml.jackson.datatype.hibernate5.PersistentCollectionSerializer.serialize(PersistentCollectionSerializer.java:243)
at com.fasterxml.jackson.databind.ser.BeanPropertyWriter.serializeAsField(BeanPropertyWriter.java:727)
at com.fasterxml.jackson.databind.ser.std.BeanSerializerBase.serializeFields(BeanSerializerBase.java:719)
at com.fasterxml.jackson.databind.ser.BeanSerializer.serialize(BeanSerializer.java:155)
at com.fasterxml.jackson.databind.ser.BeanPropertyWriter.serializeAsField(BeanPropertyWriter.java:727)
at com.fasterxml.jackson.databind.ser.std.BeanSerializerBase.serializeFields(BeanSerializerBase.java:719)
at com.fasterxml.jackson.databind.ser.BeanSerializer.serialize(BeanSerializer.java:155)
at com.fasterxml.jackson.databind.ser.std.CollectionSerializer.serializeContents(CollectionSerializer.java:145)
at com.fasterxml.jackson.databind.ser.std.CollectionSerializer.serialize(CollectionSerializer.java:107)

我知道物料清单结构本质上是递归的，但我只对上/下一层感兴趣。所以，作为1st Interactor，列出我所有的2nd Interactors，或者作为2nd Interactor，列出我所有的1st Interactors。

这是如何实现的？

标签： javajackson

解决方案

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