首页 > 解决方案 > 绘制 R 中 facet wraps 中每个组的平均数据(显示 geom_smooth)

问题描述

我有“日期”、“小时”、“日”、“工作日”、“值”的时间序列数据。我想以某种方式对数据进行分组,以便为​​我提供每个工作日(星期一、星期二等)的平均值图,但以某种方式计算某一天的平均值。例如在星期一的图中,平均值应该是数据集中所有星期一的平均值。

数据:

structure(list(Date = structure(c(1482087600, 1482084000, 1482080400, 
1482076800, 1482073200, 1482069600, 1482066000, 1482062400, 1482058800, 
1482055200, 1482051600, 1482048000, 1482044400, 1482040800, 1482037200, 
1482033600, 1482030000, 1482026400, 1482022800, 1482019200, 1482015600, 
1482012000, 1482008400, 1482004800, 1482001200, 1481997600, 1481994000, 
1481990400, 1481986800, 1481983200, 1481979600, 1481976000, 1481972400, 
1481968800, 1481965200, 1481961600, 1481958000, 1481954400, 1481950800, 
1481947200, 1481943600, 1481940000, 1481936400, 1481932800, 1481929200, 
1481925600, 1481922000, 1481918400), class = c("POSIXct", "POSIXt"
), tzone = ""), hour = c(23L, 22L, 21L, 20L, 19L, 18L, 17L, 16L, 
15L, 14L, 13L, 12L, 11L, 10L, 9L, 8L, 7L, 6L, 5L, 4L, 3L, 2L, 
1L, 0L, 23L, 22L, 21L, 20L, 19L, 18L, 17L, 16L, 15L, 14L, 13L, 
12L, 11L, 10L, 9L, 8L, 7L, 6L, 5L, 4L, 3L, 2L, 1L, 0L), day = c(18L, 
18L, 18L, 18L, 18L, 18L, 18L, 18L, 18L, 18L, 18L, 18L, 18L, 18L, 
18L, 18L, 18L, 18L, 18L, 18L, 18L, 18L, 18L, 18L, 17L, 17L, 17L, 
17L, 17L, 17L, 17L, 17L, 17L, 17L, 17L, 17L, 17L, 17L, 17L, 17L, 
17L, 17L, 17L, 17L, 17L, 17L, 17L, 17L), week = c(51, 51, 51, 
51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 
51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 
51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51), weekdays = c("Sunday", 
"Sunday", "Sunday", "Sunday", "Sunday", "Sunday", "Sunday", "Sunday", 
"Sunday", "Sunday", "Sunday", "Sunday", "Sunday", "Sunday", "Sunday", 
"Sunday", "Sunday", "Sunday", "Sunday", "Sunday", "Sunday", "Sunday", 
"Sunday", "Sunday", "Saturday", "Saturday", "Saturday", "Saturday", 
"Saturday", "Saturday", "Saturday", "Saturday", "Saturday", "Saturday", 
"Saturday", "Saturday", "Saturday", "Saturday", "Saturday", "Saturday", 
"Saturday", "Saturday", "Saturday", "Saturday", "Saturday", "Saturday", 
"Saturday", "Saturday"), Online_h = c(18L, 20L, 25L, 29L, 31L, 
32L, 30L, 23L, 24L, 17L, 15L, 15L, 10L, 9L, 7L, 7L, 9L, 12L, 
16L, 16L, 23L, 25L, 25L, 35L, 38L, 44L, 39L, 32L, 28L, 30L, 23L, 
22L, 21L, 14L, 13L, 15L, 12L, 6L, 7L, 6L, 7L, 7L, 11L, 14L, 21L, 
27L, 29L, 34L)), row.names = c(NA, 48L), class = "data.frame")

我当前的代码如下所示:

df%>%
  group_by(day) %>%
  group_by(hour) %>%
  mutate(avg_hour = mean(Value)) %>%
  ggplot(aes(x=hour, y=avg_hour)) + 
  geom_line() + 
  ylab("Available drivers") + 
  xlab("Hours") +
  facet_wrap(vars(weekdays))

这导致了这个图表。

在此处输入图像描述

但是,所有天的平均线似乎都相同,而如果针对每组天计算它应该是不同的。任何人都可以帮助我正确找到每个组的方法并将其显示在图上吗?先感谢您。

标签: rggplot2dplyrtidyversefacet-wrap

解决方案


你的group_by电话不应该像那样分开。

编辑:我注意到你在数据集中每小时只有一小时,所以不清楚你想找到的平均值是什么......

library(tidyverse)

df %>%
  group_by(weekdays, hour) %>%
  mutate(avg_drivers_online_per_hour = mean(Online_h)) %>%
  group_by(weekdays) %>% 
  mutate(avg_drivers_online_per_weekday = mean(Online_h)) %>% 
  ggplot() + 
  geom_line(aes(x=hour, y=avg_drivers_online_per_hour)) + 
  geom_segment(aes(x = 0, xend = 24, y = avg_drivers_online_per_weekday, yend = avg_drivers_online_per_weekday), color = "dodgerblue2") +
  ylab("Available drivers") + 
  xlab("Hours") +
  facet_wrap(vars(weekdays))

reprex 包于 2021-11-08 创建(v2.0.1)


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