java - Eclipse Maven XStream - 无法使字段可访问 - 模块不会“打开模型”到模块 xstream

Question

我不能让 XStream 工作，我不知道为什么。我在一个 Maven 项目中，JRE-11，MVC 模型，XStream 1.4.18。顺便说一句，我是法国人。提前致谢。我只是举了一个 UE 类的例子，但我想用“Classe”和“Creneau”来做这个。我尝试了“xstream.alias”，但没有奏效。

pom.xml

<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 https://maven.apache.org/xsd/maven-4.0.0.xsd">
  <modelVersion>4.0.0</modelVersion>
  <groupId>Archi</groupId>
  <artifactId>Archi</artifactId>
  <version>0.0.1-SNAPSHOT</version>
  <build>
    <sourceDirectory>src</sourceDirectory>
    <plugins>
      <plugin>
        <artifactId>maven-compiler-plugin</artifactId>
        <version>3.8.1</version>
        <configuration>
          <release>11</release>
        </configuration>
      </plugin>
    </plugins>
  </build>
  <dependencies>
    <dependency>
        <groupId>javax.xml</groupId>
        <artifactId>jaxb-api</artifactId>
        <version>2.1</version>
    </dependency>
    <dependency>
        <groupId>com.thoughtworks.xstream</groupId>
        <artifactId>xstream</artifactId>
        <version>1.4.18</version>
    </dependency>
  </dependencies>
</project>

Archi.java

package controlleur;

import com.thoughtworks.xstream.XStream;

import modele.*;
import vue.*;

public class Archi {
    public static void main(String[] args) {
        Classe classe = new Classe("IATIC5", 2020, 2021);
        UE ue = new UE("ARC", "EU-Archi");
        Creneau creneau = new Creneau(9, 11, 2021, 20, 22);
        
        Fenetre fenetre = new Fenetre();
        
        XStream xstream = new XStream();
        String xml = xstream.toXML(ue);
        System.out.println(xml);
        
        Controlleur controlleur = new Controlleur(classe, ue, creneau, fenetre);
    }
}

控制器.java

package controlleur;

import modele.*;
import vue.*;

public class Controlleur {  
    public Controlleur(Classe classe, UE ue, Creneau creneau, Fenetre fenetre) {
        fenetre.affiche(classe, ue, creneau);
    }
}

UE.java

package modele;

import java.util.UUID;

public class UE {
    private String id = UUID.randomUUID().toString(), sigle, nomination;

    public UE(String sigle, String nomination) {
        this.sigle = sigle;
        this.nomination = nomination;
    }

    //All getter, setter and toString
}

错误文本

Exception in thread "main" com.thoughtworks.xstream.converters.ConversionException: No converter available
---- Debugging information ----
message             : No converter available
type                : modele.UE
converter           : com.thoughtworks.xstream.converters.reflection.ReflectionConverter
message[1]          : Unable to make field private java.lang.String modele.UE.id accessible: module archi does not "opens modele" to module xstream
-------------------------------
    at xstream@1.4.18/com.thoughtworks.xstream.core.DefaultConverterLookup.lookupConverterForType(DefaultConverterLookup.java:88)
    at xstream@1.4.18/com.thoughtworks.xstream.XStream$1.lookupConverterForType(XStream.java:472)
    at xstream@1.4.18/com.thoughtworks.xstream.core.TreeMarshaller.convertAnother(TreeMarshaller.java:48)
    at xstream@1.4.18/com.thoughtworks.xstream.core.TreeMarshaller.convertAnother(TreeMarshaller.java:43)
    at xstream@1.4.18/com.thoughtworks.xstream.core.TreeMarshaller.start(TreeMarshaller.java:82)
    at xstream@1.4.18/com.thoughtworks.xstream.core.AbstractTreeMarshallingStrategy.marshal(AbstractTreeMarshallingStrategy.java:37)
    at xstream@1.4.18/com.thoughtworks.xstream.XStream.marshal(XStream.java:1243)
    at xstream@1.4.18/com.thoughtworks.xstream.XStream.marshal(XStream.java:1232)
    at xstream@1.4.18/com.thoughtworks.xstream.XStream.toXML(XStream.java:1205)
    at xstream@1.4.18/com.thoughtworks.xstream.XStream.toXML(XStream.java:1192)
    at archi/controlleur.Archi.main(Archi.java:17)

标签： javaeclipsemavenxstream