python - 从第一个 '\n' 切分列表中的所有字符串

Question

如何从列表中删除第一个 RemoveThisX\n

['RemoveThis1\nDontRemove\nDontRemove','RemoveThis2\nDontRemove\nDontRemove', 'RemoveThis3\nDontRemove\nDontRemove', 'RemoveThis4\nDontRemove\nDontRemove']

正在尝试删除 RemoveThis1\n、RemoveThis2\n、RemoveThis3、RemoveThis4\n

最终结果需要

['DontRemove\nDontRemove','DontRemove\nDontRemove', 'DontRemove\nDontRemove', 'DontRemove\nDontRemove']

标签： pythonpython-3.xlist

Answer 1

a_list = ['RemoveThis1\nDontRemove\nDontRemove','RemoveThis2\nDontRemove\nDontRemove', 'RemoveThis3\nDontRemove\nDontRemove', 'RemoveThis4\nDontRemove\nDontRemove']

result = [item[item.find('\n')+1:] for item in a_list]
print(result)

['DontRemove\nDontRemove', 'DontRemove\nDontRemove', 'DontRemove\nDontRemove', 'DontRemove\nDontRemove']