首页 > 技术文章 > 【补充版】HashMap(根据value筛选查找)

liupengpengg 2016-11-23 10:36 原文

HashMap查找之根据Value查找

一般大家都知道对于HashMap而言都是通过key来进行查找。找到了key自然对应的value也就一并找到了。但是有些情况下就需要通过value来进行判断查找。说是查找不如说筛选更为恰当。

那么什么情况下会用到这种vaule查找方式呢?让我们一起来看一下以下代码就清楚了。

【1】面向对象学生类的创建

 1 package com.java.demo_9;
 2 
 3 /**
 4  * Student类
 5  * @author liupeng
 6  *
 7  */
 8 public class Student {
 9     
10     private String stuName;
11     private String classCord;
12     private String stuNumber;
13     public String getStuName() {
14         return stuName;
15     }
16     public void setStuName(String stuName) {
17         this.stuName = stuName;
18     }
19     public String getClassCord() {
20         return classCord;
21     }
22     public void setClassCord(String classCord) {
23         this.classCord = classCord;
24     }
25     public String getStuNumber() {
26         return stuNumber;
27     }
28     public void setStuNumber(String stuNumber) {
29         this.stuNumber = stuNumber;
30     }
31     public Student() {
32         super();
33         // TODO Auto-generated constructor stub
34     }
35     public Student(String stuName,String stuNumber,String classCord) {
36         super();
37         this.stuName = stuName;
38         this.classCord = classCord;
39         this.stuNumber = stuNumber;
40     }
41     @Override
42     public String toString() {
43         return "学员名称:" + stuName + ", 学员编号:"
44         + stuNumber + ", 班级番号:" + classCord;
45     }
46     
47     
48 
49 }
Student(学生类)

【2】面向对象筛选出相同classCord的同学

package com.java.demo_9;

import java.util.ArrayList;
import java.util.HashMap;

public class HashMapTest2 {
	public static void main(String[] args) {
HashMap map = new HashMap();   //HashMap字典的创建并遍历出各个元素 System.out.println("+++++++++++++++++++++++++++++++++++++++++++++++++++++++++"); System.out.println("\t\t<学员信息一览表>\t\t"); System.out.println(); Student st1 = new Student("王小天", "cn0001", "class0001"); Student st2 = new Student("张天爱", "cn0002", "class0002"); Student st3 = new Student("武则天", "cn0003", "class0003"); Student st4 = new Student("小钢炮", "cn0004", "class0004"); Student st5 = new Student("屠龙刀", "cn0005", "class0002"); Student st6 = new Student("小龙女", "cn0008", "class0002"); Student st7 = new Student("三毛", "cn0006", "class0001"); Student st8 = new Student("杨过", "cn0007", "class0002"); map.put("王小天", st1); map.put("张天爱", st2); map.put("武则天", st3); map.put("小钢炮", st4); map.put("屠龙刀", st5); map.put("小龙女", st6); map.put("三毛", st7); map.put("杨过", st8); for (Object key : map.keySet()) { // System.out.println(key); Student value = (Student) map.get(key); System.out.println(key + ":" + value); } System.out.println("+++++++++++++++++++++++++++++++++++++++++++++++++++++++++"); System.out.println();
//创建3个ArrayList列表便于接受数据 ArrayList list1 = new ArrayList(); ArrayList list2 = new ArrayList(); ArrayList list3 = new ArrayList();
          //通过for循环,if else循环语句来筛选隶属于相同班级的学生(list3例外) for(Object key:map.keySet()){ Student obj = (Student)map.get(key); System.out.println(obj); if(obj.getClassCord().contains("class0002")){ list1.add(obj); }else if(obj.getClassCord().indexOf("class0001")!=-1){ list2.add(obj); }else{ list3.add(obj); } }

          //分别遍历出筛选过后的结果 System.out.println("+++++++++++++++++++++++++++++++++++++++++++++++++++++++++"); System.out.println("[class0002班级的学生有:]"); System.out.println(); for(Object obj:list1) System.out.println(obj); System.out.println("+++++++++++++++++++++++++++++++++++++++++++++++++++++++++"); System.out.println("[class0001班级的学生有:]"); System.out.println(); for(Object obj:list2) System.out.println(obj); System.out.println("+++++++++++++++++++++++++++++++++++++++++++++++++++++++++"); System.out.println("[其他班级的学生有:]"); System.out.println(); for(Object obj:list3) System.out.println(obj); } }

结果:

【HashMap原字典信息】

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++
		<学员信息一览表>		

三毛:学员名称:三毛, 学员编号:cn0006, 班级番号:class0001
屠龙刀:学员名称:屠龙刀, 学员编号:cn0005, 班级番号:class0002
张天爱:学员名称:张天爱, 学员编号:cn0002, 班级番号:class0002
小龙女:学员名称:小龙女, 学员编号:cn0008, 班级番号:class0002
杨过:学员名称:杨过, 学员编号:cn0007, 班级番号:class0002
小钢炮:学员名称:小钢炮, 学员编号:cn0004, 班级番号:class0004
王小天:学员名称:王小天, 学员编号:cn0001, 班级番号:class0001
武则天:学员名称:武则天, 学员编号:cn0003, 班级番号:class0003
+++++++++++++++++++++++++++++++++++++++++++++++++++++++++

【属于class0002班级学员的信息】

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++

[class0002班级的学生有:]

学员名称:屠龙刀, 学员编号:cn0005, 班级番号:class0002
学员名称:张天爱, 学员编号:cn0002, 班级番号:class0002
学员名称:小龙女, 学员编号:cn0008, 班级番号:class0002
学员名称:杨过, 学员编号:cn0007, 班级番号:class0002
+++++++++++++++++++++++++++++++++++++++++++++++++++++++++

 【属于class0001班级学员的信息】

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++
[class0001班级的学生有:]

学员名称:三毛, 学员编号:cn0006, 班级番号:class0001
学员名称:王小天, 学员编号:cn0001, 班级番号:class0001
+++++++++++++++++++++++++++++++++++++++++++++++++++++++++

  【其他班级学员的信息】

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++
[其他班级的学生有:]

学员名称:小钢炮, 学员编号:cn0004, 班级番号:class0004
学员名称:武则天, 学员编号:cn0003, 班级番号:class0003
+++++++++++++++++++++++++++++++++++++++++++++++++++++++++

 总结:

1. 创建3个ArrayList列表分别用来存放不同班级的信息.

2. 通过if ,else if ,else语句来判断属于不同班级的学生(根据classCord来判断)

3. 通过面向对象的方法调用Student类中.getClassCord()获取到classCord.

4. 通过.contains("元素"),.indexOf("元素")!=-1的任意一种方式结合if,else语句来进行筛选判断.

5. 分别遍历3个ArrayList中存入的元素.

方法很简单,相信java大神们肯定有更便捷的方法同样能够做到更好的效果。但是我是java初学者,这篇文章在此的目的只是希望能够帮助跟我一样初学java的同学们。

希望能有所帮助,谢谢。

 

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