首页 > 技术文章 > SQL Server 字符串的相似度对比

fuckcn 2014-05-17 13:27 原文

IF object_id('F_strcompare') IS NOT NULL
BEGIN 
	PRINT 'Dropping function F_strcompare'
	DROP FUNCTION F_strcompare
	IF @@ERROR = 0 PRINT 'Function F_strcompare dropped '
END 
go
CREATE FUNCTION F_strcompare(@str1 VARCHAR(8000),
                             @str2 VARCHAR(8000))
RETURNS VARCHAR(10)
AS
  BEGIN
      DECLARE @i   INT,
              @j   INT,
              @k   INT,
              @ret VARCHAR(10)

      SELECT @i = MAX(strlen),
             @j = MIN(strlen),
             @k = 0
      FROM   (SELECT strlen=Len(@str1)
              UNION
              SELECT strlen=Len(@str2)) t

      IF( @j = 0 )
        RETURN '0%'

      WHILE @j > 0
        BEGIN
            IF Substring(@str1, @j, 1) = Substring(@str2, @j, 1)
              SET @k=@k + 1

            SET @j=@j - 1
        END

      SET @ret = Rtrim(CAST(@k * 100.0 / @i AS NUMERIC(3, 0))) + '%'

      RETURN @ret
  END

GO
SELECT dbo.F_strcompare('中国人','中华人民共和国')

  

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