首页 > 技术文章 > 299. Bulls and Cows - LeetCode

okokabcd 2018-07-30 21:13 原文

Question

299. Bulls and Cows

Solution

题目大意:有一串隐藏的号码,另一个人会猜一串号码(数目相同),如果号码数字与位置都对了,给一个bull,数字对但位置不对给一个cow,注:数字对与位置对优先,一个号码不能重复判断.

思路:构造map结构,遍历实现

Java实现:实现的不漂亮,好歹能通过

public String getHint(String secret, String guess) {
    Map<Character, Index> map = new HashMap<>();
    for (int i=0; i<secret.length(); i++) {
        Index idx = map.get(secret.charAt(i));
        if (idx == null) {
            idx = new Index();
            map.put(secret.charAt(i), idx);
        }
        idx.add(i);
    }

    int bulls = 0;
    int cows = 0;
    List<Character> cowsList = new ArrayList<>(); // for count cows
    // count bulls
    for (int i=0; i<guess.length(); i++) {
        Index idx = map.get(guess.charAt(i));
        if (idx != null) { // check digits
            if (idx.isBull(i)) {
                bulls++;
            } else {
                cowsList.add(guess.charAt(i));
            }
        }
    }
    // count cows
    for (char c : cowsList) {
        Index idx = map.get(c);
        if (idx.isCow()) {
            cows++;
        }
    }
    return bulls + "A" + cows + "B";
}

class Index {
    List<Integer> idxList;
    int count;

    // constructor
    public Index() {
        idxList = new ArrayList<>();
        count = 0;
    }

    void add(int x) {
        idxList.add(x);
        count++;
    }

    boolean isCow() {
        return count-- > 0;
    }

    boolean isBull(int x) {
        for (int tmp : idxList) {
            if (x == tmp) {
                count--;
                return true;
            }
        }
        return false;
    }
}

Ref

https://leetcode.com/problems/bulls-and-cows/discuss/74621/One-pass-Java-solution

public String getHint(String secret, String guess) {
    int bulls = 0;
    int cows = 0;
    int[] numbers = new int[10];
    for (int i = 0; i<secret.length(); i++) {
        int s = Character.getNumericValue(secret.charAt(i));
        int g = Character.getNumericValue(guess.charAt(i));
        if (s == g) bulls++;
        else {
            if (numbers[s] < 0) cows++;
            if (numbers[g] > 0) cows++;
            numbers[s] ++;
            numbers[g] --;
        }
    }
    return bulls + "A" + cows + "B";
}
public String getHint(String secret, String guess) {
    int bulls = 0;
    int cows = 0;
    int[] numbers = new int[10];
    for (int i = 0; i<secret.length(); i++) {
        if (secret.charAt(i) == guess.charAt(i)) bulls++;
        else {
            if (numbers[secret.charAt(i)-'0']++ < 0) cows++;
            if (numbers[guess.charAt(i)-'0']-- > 0) cows++;
        }
    }
    return bulls + "A" + cows + "B";
}

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