首页 > 解决方案 > 使用 pdo 而不是 mysqli 时 $_SESSION 中断

问题描述

一周前,我开始使用 js 和 php 构建一个小网站。为了让人们登录,我从通过 mysqli 查询访问数据库开始,但过了一会儿我发现,使用 pdo 会是更好的主意。

php 脚本本身就像我想要的那样工作,如果登录参数正确,则返回用户。

我现在的问题是,当我使用 pdo 实现(当前在我的示例中已注释掉)时,没有 $_SESSION['user'] 了,而它使用 mysqli-query 实现。

如果我在这里错过了一些基本的东西,我不会感到惊讶,但我还没有找到解决方案。'unserialize(serialize($user))' 也只是解决我的问题的绝望尝试。只是说 $_SESSION['user'] = $user; 以同样的方式行事。

有谁知道我的代码有什么问题?我可以坚持使用工作版本,但我更喜欢使用 pdo。

在我的示例中,我使用了一个表用户,其中包含电子邮件、密码和名字列。php 文件名为 test1l.php

<!DOCTYPE html>
<html lang="en">

<head>
    <title>Test1l</title>
    <meta content="text/javascript" charset="UTF-8"/> 
</head>

<?php

    if(isset($_POST['login'])) {

        session_start();
        session_regenerate_id();

        $dbservername = "127.0.01";
        $dbusername = "username";
        $dbpassword = "password";
        $dbname = "dbname";
        $dbport = 1337;

        $conn = new mysqli($dbservername, $dbusername, $dbpassword, $dbname, $dbport);

        if ($conn->connect_error) {
            header('HTTP/1.1 901 Connection failed', true);
            header('X-PHP-Response-Code: 901', true);
        } else {

            $email = $_POST['email'];
            $password = $_POST['password'];

            $errormsg = "";

            $user = NULL;
            $sql = "SELECT * FROM user WHERE email = '" . $email . "'";

            $result = $conn->query($sql);

            $conn->close();

            if ($result->num_rows > 0) {

                $count = 0;
                while($row = $result->fetch_assoc()) {

                    if (count > 1) {
                        header('HTTP/1.1 902 Too many results', true);
                        header('X-PHP-Response-Code: 902', true);
                    }

                    $user = $row;
                    $count++;
                }

                if (password_verify($password, $user['password'])) {
                    $_SESSION['user'] = $user;
                } else {
                    header('HTTP/1.1 903 Wrong password', true);
                    header('X-PHP-Response-Code: 903', true);
                }

            } else {
                header('HTTP/1.1 904 Unknown E-Mail', true);
                header('X-PHP-Response-Code: 904', true);
            }
        }
    }
?>

<!-- 

    if(isset($_POST['login'])) {

        $email = $_POST['email'];
        $password = $_POST['password'];
        $user = NULL;

        $pdo = new PDO('mysql:host=127.0.01;dbname=dbname;port=1337', 'username', 'password');
        $statement = $pdo->prepare("SELECT * FROM user WHERE email = ?");
        $result = $statement->execute(array($email));

        if ($result === false) {
            header('HTTP/1.1 901 Login Statement failed', true);
            header('X-PHP-Response-Code: 901', true);
        } else {

            $count = 0;

            while($row = $statement->fetch()) {
                $user = $row;
                $count++;
            }

            if ($count > 1) {
                header('HTTP/1.1 902 Too many results', true);
                header('X-PHP-Response-Code: 902', true);
            } else if ($count < 1) {
                header('HTTP/1.1 904 Unknown E-Mail', true);
                header('X-PHP-Response-Code: 904', true);
            } else {
                if (password_verify($password, $user['password'])) {
                    $_SESSION['user'] = unserialize(serialize($user));
                } else {
                    header('HTTP/1.1 903 Wrong password', true);
                    header('X-PHP-Response-Code: 903', true);
                }
            }
        }
    }
-->

<body>
    <div style="display:table; margin-left:auto; margin-right:auto;">

        <?php session_start(); if(!isset($_SESSION['user'])) : ?>

            <form method="post">

                <div id="errorlogin"></div>

                <div>
                    <input type="text" placeholder="Enter E-Mail-Address" name="email" required>
                </div>
                <div>
                    <input type="password" placeholder="Enter Password" name="password"required>
                </div>

                <button type="button" class="btn-login" name="login" onclick="logMeIn(this.form.email.value, this.form.password.value)">Login</button>

                <script>

                    function logMeIn(email, password, remember) {

                        var http = new XMLHttpRequest();
                        var url = 'test1l.php';
                        var params = 'login=1&email=' + email + '&password=' + password + '&remember=' + remember;
                        http.open('POST', url, true);

                        http.setRequestHeader('Content-type', 'application/x-www-form-urlencoded');

                        http.onreadystatechange = function() {

                            if (http.readyState == 4) {

                                document.getElementById('errorlogin').innerHTML = '';

                                if (http.status == 200) {
                                    document.location = 'test1l';
                                } else if (http.status == 903 || http.status == 904) {
                                    document.getElementById('errorlogin').innerHTML += 'Incorrect email or password.';
                                } else {
                                    document.getElementById('errorlogin').innerHTML += 'Error during login: ' + http.status;
                                }
                            }
                        }
                        http.send(params);
                    }

                </script>
            </form>

        <?php else : ?>
            Hello <?php echo $_SESSION['user']['firstname']; ?>
        <?php endif; ?>
    </div>
</body>
</html>

标签: phpsessionmysqlipdo

解决方案


在注释掉的版本中,它试图在调用之前写入会话session_start


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