首页 > 解决方案 > Haskell Swagger 镜头自动生成

问题描述

我有以下代码:

import Control.Lens ((&), (.~), (?~), (%~))
import Data.Swagger (Swagger)
import Data.Swagger.Lens (paths, operationId, info, description)
import qualified Data.HashMap.Strict.InsOrd as InsOrdHashMap
import Data.Text (Text(..), pack)

genOpIds :: Swagger -> Swagger
genOpIds = paths %~ InsOrdHashMap.mapWithKey (\k v -> v & operationId ?~ (pack "hello"))

生成以下编译错误:

    • No instance for (Data.Swagger.Lens.HasOperationId
                         Data.Swagger.Internal.PathItem (Maybe Text))
        arising from a use of ‘operationId’
    • In the first argument of ‘(?~)’, namely ‘operationId’
      In the second argument of ‘(&)’, namely
        ‘operationId ?~ (pack "hello")’
      In the expression: v & operationId ?~ (pack "hello")
   |
12 | genOpIds = paths %~ InsOrdHashMap.mapWithKey (\k v -> v & operationId ?~ (pack "hello"))
   |                                                           ^^^^^^^^^^^

我发现它有点难以诊断,因为我认为 makeLenses 用于生成类实例。我正在努力看看这与以下内容有何不同(编译良好):

writeInfoTitle :: Swagger -> Swagger
writeInfoTitle = info.description ?~ (pack "whatever description")

因为所涉及的类型层次结构在底部是相似的。我怀疑我在这里缺少基本的理解,但是我已经阅读了镜头教程,包括遍历部分;仆人招摇代码的各种位,以及其他一些示例,并没有设法弄清楚这一点。

要轻松重新创建错误消息,您可以克隆以下 repo 和stack build

https://github.com/msk-/improved-spork

标签: haskellswaggerhaskell-lens

解决方案


免责声明:我从未使用过 Swagger。但是,查看它的文档,我可以在 Swagger 类型中看到以下元素:
_swaggerPaths :: InsOrdHashMap FilePath PathItem- 对应于paths镜头。
查看 的定义PathItem表明它不是一个实例HasOperationId- 它本身是由

PathItem     
  _pathItemGet :: Maybe Operation   
  _pathItemPut :: Maybe Operation   
  _pathItemPost :: Maybe Operation  
  _pathItemDelete :: Maybe Operation    
  _pathItemOptions :: Maybe Operation   
  _pathItemHead :: Maybe Operation  
  _pathItemPatch :: Maybe Operation 
  _pathItemParameters :: [Referenced Param]

这似乎表明您在中缺少镜头构图
(\k v -> v & (??? . operationId) ?~ (pack "hello"));类似于
(\k v -> v & (itemGet . operationId) ?~ (pack "hello"))

编辑:看起来您想要实现的目标(设置简单的路径操作)可以通过使用记录的Monoid实例轻松完成PathItem,如下所示:

genOpsId = paths %~ InsOrdHashMap.mapWithKey (\k v -> v & get ?~ (mempty & operationId ?~ (pack "hello")))



编辑#2:根据要求,这是一种遍历PathItem记录字段并设置存在的那些的 operationId 的方法。
作为记录,我很确定有一种方式,方式,方式更清洁的方式来做到这一点,但这里有。

dokey :: PathItem -> PathItem
dokey v = foldl 
  (\acc nv -> acc & nv %~ (fmap $ operationId ?~ (pack "hello")))
  v 
  [get, put, post, delete, options, head_, patch]  

genOpIds :: Swagger -> Swagger
genOpIds = paths %~ InsOrdHashMap.mapWithKey (\k -> doKey)


希望能帮助到你!:)


推荐阅读