python-3.x - 为什么 any() 和 all() 在处理布尔值时效率低下?
问题描述
我在玩的时候才意识到一些事情timeit
,and, or, any(), all()
我想我可以在这里分享。这是衡量性能的脚本:
def recursion(n):
"""A slow way to return a True or a False boolean."""
return True if n == 0 else recursion(n-1)
def my_function():
"""The function where you perform all(), any(), or, and."""
a = False and recursion(10)
if __name__ == "__main__":
import timeit
setup = "from __main__ import my_function"
print(timeit.timeit("my_function()", setup=setup))
以下是一些时间安排:
a = False and recursion(10)
0.08799480279344607
a = True or recursion(10)
0.08964192798430304
正如预期的那样,True or recursion(10)
计算False and recursion(10)
速度非常快,因为只有第一项很重要,并且操作立即返回。
a = recursion(10) or True # recursion() is False
1.4154556830951606
a = recursion(10) and False # recursion() is True
1.364157978046478
拥有or True
or and False
in the line 并不会加快此处的计算速度,因为它们是第二次评估的,并且必须首先执行整个递归。虽然烦人,但这是合乎逻辑的,并且遵循操作优先级规则。
更令人惊讶的是,无论哪种情况all()
,any()
总是表现最差:
a = all(i for i in (recursion(10), False))) # recursion() is False
1.8326778537880273
a = all(i for i in (False, recursion(10))) # recursion() is False
1.814645767348111
我本来预计第二次评估会比第一次评估快得多。
a = any(i for i in (recursion(10), True))) # recursion() is True
1.7959248761901563
a = any(i for i in (True, recursion(10))) # recursion() is True
1.7930442127481
同样未达到的期望在这里。
因此,如果性能在您的应用程序中很重要,那么它似乎any()
并且all()
远不是分别编写 bigor
和 big的便捷方式。and
这是为什么?
编辑:根据评论,元组生成似乎很慢。我看不出 Python 本身不能使用它的原因:
def all_faster(*args):
Result = True
for arg in args:
if not Result:
return False
Result = Result and arg
return True
def any_faster(*args):
Result = False
for arg in args:
if Result:
return True
Result = Result or arg
return False
它已经比内置函数更快,并且似乎具有短路机制。
a = faster_any(False, False, False, False, True)
0.39678611016915966
a = faster_any(True, False, False, False, False)
0.29465180389252055
a = faster_any(recursion(10), False) # recursion() is True
1.5922580174283212
a = faster_any(False, recursion(10)) # recursion() is True
1.5799157924820975
a = faster_all(False, recursion(10)) # recursion() is True
1.6116566893888375
a = faster_all(recursion(10), False) # recursion() is True
1.6004807187900951
Edit2:好吧,一个接一个地传递参数会更快,但生成器会更慢。
解决方案
实际上,any()
IS 等价于 a chain ofor
并且all()
IS 等价于 chain of and
,包括短路。问题在于您执行基准测试的方式。
考虑以下:
def slow_boolean_gen(n, value=False):
for x in range(n - 1):
yield value
yield not value
generator = slow_boolean_gen(10)
print([x for x in generator])
# [False, False, False, False, False, False, False, False, False, True]
以及以下微基准:
%timeit generator = slow_boolean_gen(10, True); next(generator) or next(generator) or next(generator) or next(generator) or next(generator) or next(generator) or next(generator) or next(generator) or next(generator) or next(generator)
# 492 ns ± 35.7 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)
%timeit generator = slow_boolean_gen(10, False); next(generator) or next(generator) or next(generator) or next(generator) or next(generator) or next(generator) or next(generator) or next(generator) or next(generator) or next(generator)
# 1.18 µs ± 12.4 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)
%timeit generator = slow_boolean_gen(10, True); next(generator) and next(generator) and next(generator) and next(generator) and next(generator) and next(generator) and next(generator) and next(generator) and next(generator) and next(generator)
# 1.19 µs ± 11.7 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)
%timeit generator = slow_boolean_gen(10, False); next(generator) and next(generator) and next(generator) and next(generator) and next(generator) and next(generator) and next(generator) and next(generator) and next(generator) and next(generator)
# 473 ns ± 6.27 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)
%timeit generator = slow_boolean_gen(10, True); any(x for x in generator)
# 745 ns ± 15 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)
%timeit generator = slow_boolean_gen(10, False); any(x for x in generator)
# 1.29 µs ± 12.4 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)
%timeit generator = slow_boolean_gen(10, True); all(x for x in generator)
# 1.3 µs ± 22.4 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)
%timeit generator = slow_boolean_gen(10, False); all(x for x in generator)
# 721 ns ± 8.05 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)
%timeit generator = slow_boolean_gen(10, True); any([x for x in generator])
# 1.03 µs ± 28.8 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)
%timeit generator = slow_boolean_gen(10, False); any([x for x in generator])
# 1.09 µs ± 27.7 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)
%timeit generator = slow_boolean_gen(10, True); all([x for x in generator])
# 1.05 µs ± 11.1 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)
%timeit generator = slow_boolean_gen(10, False); all([x for x in generator])
# 1.02 µs ± 11.9 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)
您可以清楚地看到短路正在起作用,但是如果您首先构建list
,这需要一个恒定的时间来抵消您从短路中获得的任何性能增益。
编辑:
手动实现不会给我们带来任何性能提升:
def all_(values):
result = True
for value in values:
result = result and value
if not result:
break
return result
def any_(values):
result = False
for value in values:
result = result or value
if result:
break
return result
%timeit generator = slow_boolean_gen(10, True); any_(x for x in generator)
# 765 ns ± 6.76 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)
%timeit generator = slow_boolean_gen(10, False); any_(x for x in generator)
# 1.48 µs ± 8.97 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)
%timeit generator = slow_boolean_gen(10, True); all_(x for x in generator)
# 1.47 µs ± 5.71 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)
%timeit generator = slow_boolean_gen(10, False); all_(x for x in generator)
# 765 ns ± 8.76 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)
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