首页 > 解决方案 > 在尚未启动的池工作人员中捕获异常

问题描述

我正在尝试在子进程中捕获异常。如果工人数量 == 任务数量,我的代码(见下文)可以正常工作。但是,如果工作人员比示例中的任务多,则尚未启动的 2 个进程将抛出相同的异常,但我在 MainProcess 和子进程中都无法捕获它。

from multiprocessing import Pool, current_process
import time
from exceptions import GracefulExit
import signal


def terminate_handler(signum, frame):
    print(dir(frame))
    if current_process().name == 'MainProcess':
        # we will not raise error if process
        # is main because we need to finish all the jobs
        return
    raise GracefulExit()


def test_func(val):
    i = 0
    try:
        while True:
            time.sleep(0.1)
            i += 1
            if i >= 10:
                return i
    except GracefulExit:
        pass
    return i


if __name__ == "__main__":
    signal.signal(
            signal.SIGINT, terminate_handler)
    try:
        with Pool(5) as p:
            r = p.map(test_func, [1, 2, 3])
    except GracefulExit:
        pass
    print(r)

标签: pythonmultiprocessing

解决方案


我能建议什么,选择任何变体:

  1. 确保任务数量不小于工人数量,只需添加存根(例如None)以确保所有工人都将启动

  2. runPool的Process的override方法:

    class CustomProcess(Process):
        def run(self):
            try:
                super().run()
            except GracefulExit:
                print('interrupted idle worker')
    
    
    class CustomPool(multiprocessing.pool.Pool):
        Process = CustomProcess
    
    ....
    
    with CustomPool(5) as p:
       r = p.map(test_func, [1, 2, 3])
    
  3. 编写自己的池实现


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