php - 将树转换为 PHP 中的完整路径列表
问题描述
我正在尝试将树结构转换为路径列表。
树看起来像这样:
array (
0 =>
array (
'name' => 'Default Category',
'children' =>
array (
0 =>
array (
'name' => 'Carpet',
'children' =>
array (
0 =>
array (
'name' => 'Colour',
'children' =>
array (
0 =>
array (
'name' => 'White',
'children' =>
array (
),
),
1 =>
array (
'name' => 'Grey',
'children' =>
array (
),
),
2 =>
array (
'name' => 'Black',
'children' =>
array (
),
),
3 =>
array (
'name' => 'Light',
'children' =>
array (
),
),
4 =>
array (
'name' => 'Medium',
'children' =>
array (
),
),
5 =>
array (
'name' => 'Dark',
'children' =>
array (
),
),
),
),
1 =>
array (
'name' => 'Style',
'children' =>
array (
0 =>
array (
'name' => 'Twist Pile Carpets',
'children' =>
array (
),
),
1 =>
array (
'name' => 'Stainfree Carpets',
'children' =>
array (
),
),
2 =>
array (
'name' => 'Saxony and Shagpile Carpets',
'children' =>
array (
),
),
3 =>
array (
'name' => 'Soft Carpets',
'children' =>
array (
),
),
4 =>
array (
'name' => 'Loop Pile & Berber Carpets',
'children' =>
array (
),
),
5 =>
array (
'name' => 'Wool Carpets',
'children' =>
array (
),
),
6 =>
array (
'name' => 'Striped & Patterned Carpet',
'children' =>
array (
),
),
7 =>
array (
'name' => 'Natural Carpets',
'children' =>
array (
),
),
),
),
我的最终结果将是一个如下所示的数组:
Default Category/
Default Category/Carpet
Default Category/Carpet/Colour
Default Category/Carpet/Colour/White
Default Category/Carpet/Colour/Grey
Default Category/Carpet/Colour/Black
...
Default Category/Carpet/Style/
Default Category/Carpet/Style/Twist Pile Carpets
Default Category/Carpet/Style/Stainfree Carpets
我知道我需要在这里使用递归并且可以迭代树,但是我不确定如何在遍历树时构建路径列表。
我尝试过搜索,但没有找到任何接近我特别需要的东西,而且我似乎有这样的印象,即我正在使用的树是一棵多路树,这与处理略有不同。
一些建议是简化树,但我已经通过删除其他不必要的键来做到这一点,并且我已经看到了扁平化数组以使遍历过程更容易的建议,但我也不清楚这将如何工作。
任何帮助,将不胜感激。
更新 2
这是我目前拥有的,它适用于第一条路径,即:默认类别/地毯/颜色/白色,但第二条路径不会携带默认类别/地毯/颜色/,这最终是我想要弄清楚的出来怎么办。
function generateCategoryPaths($categoryTree, &$paths = null, &$path = null)
{
if (! $paths) {
$paths = [];
}
foreach ($categoryTree as $category) {
$path .= $category['name'];
if (isset($category['children']) && count($category['children']) > 0) {
$path .= '/';
generateCategoryPaths($category['children'], $paths, $path, $level);
continue;
}
$paths[] = $path;
$path = '';
}
return $paths;
}
并调用代码:
$categoryPaths = generateCategoryPaths($categories);
这将返回以下内容:
array (
0 => 'Default Category/Carpet/Colour/White',
1 => 'Grey',
2 => 'Black',
3 => 'Light',
4 => 'Medium',
5 => 'Dark',
6 => 'Style/Twist Pile Carpets',
7 => 'Stainfree Carpets',
8 => 'Saxony and Shagpile Carpets',
9 => 'Soft Carpets',
10 => 'Loop Pile & Berber Carpets',
11 => 'Wool Carpets',
12 => 'Striped & Patterned Carpet',
13 => 'Natural Carpets',
14 => 'Brand',
15 => 'Room/Bedroom Carpet',
16 => 'Living Room Carpet',
17 => 'Hall, Stairs & Landing Carpet',
18 => 'Office Carpet',
19 => 'Conservatory Carpet',
20 => 'Dining Room Carpet',
21 => 'Whole House',
22 => 'Vinyl/Colour/White',
23 => 'Grey',
24 => 'Black',
25 => 'Light',
26 => 'Medium',
27 => 'Dark',
28 => 'Style/Wood Effect Luxury Vinyl Flooring',
29 => 'Tile Effect Luxury Vinyl Flooring',
30 => 'Parquet Luxury Vinyl Flooring',
31 => 'Plain',
32 => 'Brand/Naturelle',
33 => 'TLC',
34 => 'Karndean Flooring',
35 => 'Polyflor Flooring',
36 => 'Amtico',
37 => 'Quickstep Livyn',
38 => 'COREtec Flooring',
39 => 'Installation/Click Vinyl Flooring',
40 => 'Stick Down Vinyl Flooring',
41 => 'Laminate/Colour/White',
第一行是我试图为每个条目复制它,它显示了通过树的路径。
第二行和后续行将丢弃当前路径,这就是我要解决的问题。
更新 3
输入树的 JSON 编码版本:
[{"name":"Default Category","level":"1","children":[{"name":"Carpet","level":"2","children":[{"name":"Colour","level":"3","children":[{"name":"White","level":"4","children":[]},{"name":"Grey","level":"4","children":[]},{"name":"Black","level":"4","children":[]},{"name":"Light","level":"4","children":[]},{"name":"Medium","level":"4","children":[]},{"name":"Dark","level":"4","children":[]}]},{"name":"Style","level":"3","children":[{"name":"Twist Pile Carpets","level":"4","children":[]},{"name":"Stainfree Carpets","level":"4","children":[]},{"name":"Saxony and Shagpile Carpets","level":"4","children":[]},{"name":"Soft Carpets","level":"4","children":[]},{"name":"Loop Pile & Berber Carpets","level":"4","children":[]},{"name":"Wool Carpets","level":"4","children":[]},{"name":"Striped & Patterned Carpet","level":"4","children":[]},{"name":"Natural Carpets","level":"4","children":[]}]}]}]}]
解决方案
我创建了一个树生成器,它创建了一个<ul>'s
with<li>'s
可以包含其他<ul>'s
and <li>'s
。你可以在这里阅读我的博客文章https://delboy1978uk.wordpress.com/2014/12/06/tree-generator-for-multi-dimensional-arrays/
这不完全是您正在寻找的东西,但调整这个类以生成斜杠而不是打开/关闭标签应该不会太难!回归策略才是最重要的!祝你好运!
class Tree
{
private $data;
private $html;
public function buildTree(array $data, $parent_id)
{
$this->data = $data;
$this->html = '<ul>';
$this->getChildren($parent_id);
$this->html .= '</ul>';
return $this->html;
}
private function getChildren($parentId)
{
$children = array();
foreach ($this->data as $row) {
if ($row['parentid'] == $parentId) {
$children[] = $row;
}
}
foreach($children as $child)
{
$this->html .= '<li>'.$child['name'].'<ul>';
$this->getChildren($child['id']);
$this->html .= '</ul></li>';
}
}
}
$tree = new Tree();
$ul = $tree->buildTree($data, 0);
echo $ul;
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