首页 > 解决方案 > 如何在 R 中并行运行 for 循环

问题描述

假设我有一个函数f()和一个向量d

f <- function(x) dexp(x, 2)
d <- runif(10, 1, 5)

现在我想执行一个 for 循环

dnew <- numeric(length(d))
for (i in seq_along(dnew)){
   dnew[i] <- f(d[i])
}

. 我怎样才能并行执行此操作?

标签: rparallel-processingparallel.foreach

解决方案


  • 示例代码在没有 for 循环的情况下更快:

    dnew2 <- f(d)          # 'f()' and 'd' from question
    all.equal(dnew, dnew2) # 'dnew' from question 
    [1] TRUE
    
    library(microbenchmark)
    microbenchmark('for loop' = for (i in seq_along(dnew)){ dnew[i] <- f(d[i]) },
                   'vectorized' = { dnew2 = f(d) })
    Unit: microseconds
           expr    min      lq     mean  median     uq    max neval
       for loop 15.639 16.4455 17.66640 17.0045 18.089 43.938   100
     vectorized  1.249  1.3140  1.44039  1.3845  1.516  2.424   100
    
  • 它可以与foreach并行化:

    library(foreach)
    library(doParallel); registerDoParallel(2)
    dnew3 <- foreach(i=seq_along(dnew), .combine=c) %dopar% {
        f(d[i])
    }
    all.equal(dnew, dnew3)
    [1] TRUE
    

    并行化版本较慢,因为并行开销大于收益。

    microbenchmark('for loop' = for (i in seq_along(dnew)){ dnew[i] <- f(d[i]) },
                   'foreach' = { dnew3 <- foreach(i=seq_along(dnew), .combine=c) %dopar% {
                                          f(d[i]) } 
                                })
    Unit: microseconds
         expr       min        lq        mean     median         uq       max neval
     for loop    17.799    22.048    31.01027    32.7615    37.0945    67.265   100
      foreach 11875.845 13003.558 13576.64759 13427.1015 14041.3455 17782.638   100
    
  • 如果f()需要更多时间进行评估,则foreach版本更快:

    f <- function(x){
        Sys.sleep(.3)
        dexp(x, 2)
    }
    microbenchmark('for loop' = for (i in seq_along(dnew)){ dnew[i] <- f(d[i]) },
                   'foreach' = {dnew3 <- foreach(i=seq_along(dnew), .combine=c) %dopar% {
                                         f(d[i]) }
                    }, times=2)
    Unit: seconds
         expr      min       lq     mean   median       uq      max neval
     for loop 3.004271 3.004271 3.004554 3.004554 3.004837 3.004837     2
      foreach 1.515458 1.515458 1.515602 1.515602 1.515746 1.515746     2
    

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