首页 > 解决方案 > 字符串复制中字母的范围位置

问题描述

我有一个像"abc1abc1".

我想要做的是加粗字符串的每个数字。我已经绘制了下面的代码。它通过分隔字符串的每个字符并将它们放入一个数组来工作。然后,在一个循环中,如果每个字符都包含一个Int(),则该字符是粗体的。

但是,当有两个相同的 Int 时,问题就来了。在上面的字符串中,有 2 个字符 1,因此代码只会将第一个字符加粗。

// Bold the numbers
    let fullString = "abc1abc1"
    let characters = Array(fullString)
    let mutableString = NSMutableAttributedString(string: fullString)
    for item in characters {
        let string = String(item)
        let decimalCharacters = CharacterSet.decimalDigits
        let decimalRange = string.rangeOfCharacter(from: decimalCharacters)
        if decimalRange != nil {
            let str = NSString(string: fullString)
            let range = str.range(of: string)
            mutableString.addAttribute(NSAttributedStringKey.foregroundColor, value: UIFont.systemFont(ofSize: 18, weight: .heavy), range: range)
        }
    }
    instructionsLabel.attributedText = mutableString

// characters = ["a", "b", "c", "1", "a", "b", "c", "1"]
// range of ints returns {3, 1} and {3, 1}
// range of ints SHOULD return {3, 1} and {7, 1}

标签: swiftstring

解决方案


尝试这个:

let fullString = "abc1abc1"
let range = NSRange(location: 0, length: (fullString as NSString).length)
let mutableString = NSMutableAttributedString(string: fullString)
let regex = try! NSRegularExpression(pattern: "[0-9]")
let matches = regex.matches(in: fullString, range: range)

for match in matches {
    mutableString.addAttributes([.font: UIFont.systemFont(ofSize: 18, weight: .heavy)], range: match.range)
}

instructionsLabel.attributedText = mutableString

推荐阅读