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django - 在单个模板中编写 django 多个视图

问题描述

这里只有 Random_number 函数正常工作，但随机密码函数甚至没有给出控制台输出我想将生成的密码返回给 html 模板。代码有问题吗？

意见

def random_number(request):
    random_num = ''
    if(request.POST.get('Submit-Number')): 
        min_number = int(request.POST.get('min_number'))
        max_number = int(request.POST.get('max_number')) 
    random_num = random.randint(min_number,max_number)
    return render(request,'random_number/random-number.html'), 
    {'random_num':random_num})

def random_password(request):
    random_pass = ''
    if(request.POST.get('Get-Password')):
        min_length = int(request.POST.get('min_length'))
        #max_length = int(request.POST.get('max_length'))
        all_char = 'abcdefghijklmnopqrstuvwxyz123456789!@#$%^&*()'
        for eve in range(min_length):
            new_word += random.choice(all_char)
        random_pass = new_word
        print(random_pass)
    return render(request,'random_number/random-number.html', 
    {'random_pass':random_pass})

模板

</head>
<body>
    <div class="container">
        <div class="row">
        <div class="col-md-6">1</div>
    <h3> Generate Random Number Here </h3>
    <form class="" action="#" method="POST"> <!-- method is posting and 
      refreshing page with new Data over Random Number -->
      <input type="number" name="min_number" value="1">
      <input type="number" name="max_number" value="10">
      {% csrf_token %}
      <input type="submit" name="Submit-Number" value="SUBMIT">
    </form>
    <!-- <h3> Random Number = {{ random_num }}</h3>  -->
  </div>
  <div class="col-md-6">2</div>
  <h3> Generate Random Password Here </h3>
  <form class="" action="#" method="POST"> <!-- method is posting and 
    refreshing page with new Data over Random Number -->
    <input type="number" name="min_length" value="8">
    <input type="number" name="max_length" value="12">
    {% csrf_token %}
    <input type="submit" name="Get-Password" value="SUBMIT">
  </form>
  <h3> Password = {{ random_pass }}</h3>
  </div>
</div>

标签： djangodjango-templatesdjango-views

解决方案

使用 random_password 中的调试器来检查代码失败的原因。这将帮助您检查您是否正在输入该功能。导入pdb；pdb.set_trace()

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