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php - Doctrine 2 - 如何在多个 addSelect 中添加限制

问题描述

问题：运行查询时出错

{
    "status": false,
    "error": {
        "classname": "Doctrine\\ORM\\Query\\QueryException",
        "message": "[Syntax Error] line 0, col 783: Error: Expected Doctrine\\ORM\\Query\\Lexer::T_CLOSE_PARENTHESIS, got 'LIMIT'"
    }
}

如何在以下查询中的addSelect中添加限制。

 $qb = $this->em->createQueryBuilder();
    $qb->select("identity(igsm.group) as group_id,
    qp.id AS q_paper_id,
    qp.name AS q_name,
    qp.description AS q_description,        
    qp.marks,
    identity(qp.questionPaperStatus) AS qpStatus,
    qp.timeInMinutes as time_in_minutes,
    sa.marks as marks_obtained,
    sa.id AS assessment_id");
    $qb->addSelect("(SELECT IfElse(count(qps.id) > 0 , TRUE, FALSE) FROM Entity\QuestionPaper qps "
            . "WHERE qps.createdBy = :userId AND qps.id = qp.id) as flag");
    $qb->addSelect("(SELECT count(qpe.id) from Entity\QuestionPaperEvaluation qpe "
            . "where qpe.questionPaper = qp.id AND qpe.user = :userId) as student_evaluation_cnt");
    $qb->addSelect("(SELECT LOWER(ats.assignee) from Entity\AssessmentTimelineStatus ats, Entity\AssessmentStudentTimeline ast "
            . "WHERE ast.assessmentTimelineStatus = ats.id AND ast.user = igsm.user AND ast.assessment = qp.id "
            . "ORDER BY ats.id DESC LIMIT 1) AS assignee");
    $qb->addSelect("(SELECT identity(ast.assessmentTimelineStatus) from Entity\AssessmentTimelineStatus ats, Entity\AssessmentStudentTimeline ast "
            . "WHERE ast.assessmentTimelineStatus = ats.id AND ast.user = igsm.user AND ast.assessment = qp.id "
            . "ORDER BY ats.id DESC LIMIT 1) AS assessment_timeline_id");
    $qb->addSelect("(SELECT UPPER(ConcatWs(' ', ats.action,ats.item)) as assesment_submissions from Entity\AssessmentTimelineStatus ats, "
            . "Entity\AssessmentStudentTimeline ast WHERE ast.assessmentTimelineStatus = ats.id AND ast.user = igsm.user AND ast.assessment = qp.id "
            . "ORDER BY ats.id DESC LIMIT 1) AS action");
    $qb->from('Entity\QuestionPaperGroupStudentMap', 'qpgsm');
    $qb->innerJoin('Entity\InstituteGroupStudentMap', 'igsm', 'WITH', 'igsm.id=qpgsm.instituteGroupStudentMap');
    $qb->innerJoin('Entity\QuestionPaper', 'qp', 'WITH', 'qp.id=qpgsm.questionPaper AND qp.questionPaperStatus > 4');
    $qb->leftJoin('Entity\AssesmentSubmissions', 'sa', 'WITH', 'sa.assesmentId = qp.id AND sa.userId = igsm.user');
    $qb->leftJoin('Entity\PackageQuestionPaperHistory', 'pqph', 'WITH', 'pqph.questionPaperId = qp.id');
    $qb->where('igsm.user = :userId')->setParameter(':userId', $userId);
    $qb->andWhere("igsm.group IN (:GroupIds)")->setParameter(':GroupIds', explode(",", $groupId));
    $qb->orderBy('qpgsm.id', 'DESC');
    $qb->setMaxResults(1);
    $result = $qb->getQuery()->getResult();
    return $result;

尽管子查询依赖于主查询，但我可以单独放置子查询吗？如何在我的子查询中添加限制。

谢谢。

标签： phpmysqldoctrine-ormcodeigniter-3

解决方案

github中有一个关于这个的问题。

有人问过同样的问题：

一个可能的快速破解解决方案可能是：

  • 在选择语句中使用“ order by”列添加所需的选择列
  • 使用MIN 或 MAX聚合结果以获得第一个结果（与 LIMIT 1 具有相同的结果）

此子选择：

$qb->addSelect("(SELECT LOWER(ats.assignee) from Entity\AssessmentTimelineStatus ats, Entity\AssessmentStudentTimeline ast "
        . "WHERE ast.assessmentTimelineStatus = ats.id AND ast.user = igsm.user AND ast.assessment = qp.id "
        . "ORDER BY ats.id DESC LIMIT 1) AS assignee");

将被写为：

$qb->addSelect("(SELECT MAX(concat(ats.id, ' ', LOWER(ats.assignee))) from Entity\AssessmentTimelineStatus ats, Entity\AssessmentStudentTimeline ast "
        . "WHERE ast.assessmentTimelineStatus = ats.id AND ast.user = igsm.user AND ast.assessment = qp.id "
        . "ORDER BY ats.id DESC) AS assignee");

当您获得“assignee”值时，您可以拆分为第一个空白值并获得“LOWER(ats.assignee)”的值。

$result = explode(' ',$assignee, 2);

ORDER BY 为 DESC 时使用 MAX，ASC 时使用 MIN。

这是因为 MAX 或 MIN 聚合函数只选择最高或最低值，它可以是数字或字符串。

参考

最大/最小 mysql 文档

爆炸到第一个空白字符

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