首页 > 解决方案 > 使用 toSplit() 方法拆分后如何使用字符串声明人员对象?

问题描述

我为自己制作了字符串,例如:

johnName = parts[0]
johnSurname = parts[1]
.
.
.

但是如果我有 100 个人而不是 3 个人呢?那么如何将字符串数组值放入对象中呢?

String text = "John.Davidson/05051988/Belgrade Michael.Barton/01011968/Krakov Ivan.Perkinson/23051986/Moscow";
    String[] parts = text.split("[./ ]+" );

    String johnIme = parts[0];
    String johnPrezime = parts[1];
    String johnDatum = parts[2];
    String johnMesto = parts[3];

    String michaelIme = parts[4];
    String michaelPrezime = parts[5];
    String michaelDatum = parts[6];
    String michaelMesto = parts[7];

    String ivanIme = parts[8];
    String ivanPrezime = parts[9];
    String ivanDatum = parts[10];
    String ivanMesto = parts[11];


    Person john = new Person(johnIme, johnPrezime, datumJohn, johnMesto);
    Person michael = new Person(michaelIme,michaelPrezime,datumMichael ,michaelMesto);
    Person ivan = new Person(ivanIme,ivanPrezime,datumIvan ,ivanMesto);

人:
Ime:John
Prezime:戴维森
数据:1988-05-05
Mesto:贝尔格莱德

人:
Ime:Michael
Prezime:Barton
Datum:1968-01-01
Mesto: Krakov

人:
Ime:Ivan
Prezime:Perkinson
数据:1986-05-23
Mesto:莫斯科

标签: java

解决方案


你会使用一个循环和一个数组Person(或者List<Person>如果你愿意的话):

// ASSERTION: parts.length % 4 == 0
Person[] people = new Person[parts.length / 4];
int peopleIndex = 0;
for (int i = 0; i < parts.length; i += 4) {
    people[peopleIndex++] = new Person(parts[i], parts[i + 1], parts[i + 2], parts[i + 3]);
}

我想你甚至不需要peopleIndex

// ASSERTION: parts.length % 4 == 0
Person[] people = new Person[parts.length / 4];
for (int i = 0; i < parts.length; i += 4) {
    people[i / 4] = new Person(parts[i], parts[i + 1], parts[i + 2], parts[i + 3]);
}

使用List<Person>

// ASSERTION: parts.length % 4 == 0
List<Person> people = new LinkedList<>(); // Or new ArrayList<>(parts.length / 4), or...
for (int i = 0; i < parts.length; i += 4) {
    people.push(new Person(parts[i], parts[i + 1], parts[i + 2], parts[i + 3]));
}

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