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php - 如何使用 mysql 使用 php 中的按钮删除一行

问题描述

我在从表中删除行时遇到问题。当我单击“删除”按钮时，它确实将我带到了下一页，并显示“从播放器中删除了 0 行”。基本上，它执行正确，但我无法删除选定的行。我已经能够显示并添加到表格中。

播放器.php

<table id="table table-bordered">
<tr>
    <th>Id#</th>
    <th>Player(s)</th>
    <th>Position</th>
</tr>


if(!($stmt = $mysqli->prepare("SELECT id_Player, name_Player, position_Player FROM player s ORDER BY position_Player ASC"))){
echo "Prepare failed: "  . $mysqli->connect_errno . " " . $mysqli->connect_error;
}

if(!$stmt->execute())
{
echo "Execute failed: "  . $mysqli->connect_errno . " " . $mysqli->connect_error;
}
if(!$stmt->bind_result($id_Player, $name_Player, $position_Player))
{
 echo "Bind failed: "  . $mysqli->connect_errno . " " . $mysqli->connect_error;   
}

    while($stmt->fetch()){
    echo "<tr><td>  $id_Player </td> <td>  $name_Player </td><td>  $position_Player  </td>";

    ?>
        <td>
            <form id="delete" method="post" action="deletePlayers.php">

                <input type="submit" name="id_Player" value="Delete!"/>    

            </form>
        </td>
    </tr>

删除播放器.php

if(!($stmt = $mysqli->prepare("DELETE FROM player WHERE id_Player  = ?"))){
    echo "Prepare failed: "  . $stmt->errno . " " . $stmt->error;}
if(!($stmt->bind_param("s",$_POST['id_Player']))){
    echo "Bind failed: "  . $stmt->errno . " " . $stmt->error;}
if(!$stmt->execute()){
    echo "Execute failed: "  . $stmt->errno . " " . $stmt->error;}     
else {
    echo "Removed " . $stmt->affected_rows . " row from player. <br/><br/><strong> Returning to 'Add Players'</strong>";}

标签： phpmysqlsqlpostbutton

解决方案

问题在于这行代码，

if(!($stmt->bind_param("s",$_POST['id_Player']))){}

这里的值$POST['id_player']是Delete!因为您在 HTML 代码中传递了输入类型提交的名称，并且我认为您的数据库中没有任何 id 等于Delete!。

解决方案

你需要做的是你需要使用一个隐藏的输入来保存这样的id_Player值，

if(!($stmt = $mysqli->prepare("SELECT id_Player, name_Player, position_Player FROM player s ORDER BY position_Player ASC"))){
echo "Prepare failed: "  . $mysqli->connect_errno . " " . $mysqli->connect_error;
}

if(!$stmt->execute())
{
echo "Execute failed: "  . $mysqli->connect_errno . " " . $mysqli->connect_error;
}
if(!$stmt->bind_result($id_Player, $name_Player, $position_Player))
{
 echo "Bind failed: "  . $mysqli->connect_errno . " " . $mysqli->connect_error;   
}

    while($stmt->fetch()){
    echo "<tr><td>  $id_Player </td> <td>  $name_Player </td><td>  $position_Player  </td>";

    ?>
        <td>
            <form id="delete" method="post" action="deletePlayers.php">
                <input type="hidden" name="id_Player" value="<?= $id_Player ?>"/>
                <input type="submit" value="Delete!"/>    

            </form>
        </td>
    </tr>

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