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python - 简化许多 if 语句

问题描述

有没有办法简化这堆 if 语句？这个解析函数确实有效（使用正确的字典），但它必须为输入中的每个单词测试 6 个 if 语句。对于一个 5 个单词的句子，这将是 30 个 if 语句。它也有点难以阅读。

def parse(text):
    predicate=False
    directObjectAdjective=False
    directObject=False
    preposition=False
    indirectObjectAdjective=False
    indirectObject=False
    text=text.casefold()
    text=text.split()
    for word in text:
        if not predicate:
            if word in predicateDict:
                predicate=predicateDict[word]
                continue
        if not directObjectAdjective:
            if word in adjectiveDict:
                directObjectAdjective=adjectiveDict[word]
                continue
        if not directObject:
            if word in objectDict:
                directObject=objectDict[word]
                continue
        if not preposition:
            if word in prepositionDict:
                preposition=prepositionDict[word]
                continue
        if not indirectObjectAdjective:
            if word in adjectiveDict:
                indirectObjectAdjective=adjectiveDict[word]
                continue
        if not indirectObject:
            if word in objectDict:
                indirectObject=objectDict[word]
                continue
    if not directObject and directObjectAdjective:
        directObject=directObjectAdjective
        directObjectAdjective=False
    if not indirectObject and indirectObjectAdjective:
        indirectObject=indirectObjectAdjective
        indirectObjectAdjective=False
    return [predicate,directObjectAdjective,directObject,preposition,indirectObjectAdjective,indirectObject]

如果需要，这里还有一个字典样本。

predicateDict={
"grab":"take",
"pick":"take",
"collect":"take",
"acquire":"take",
"snag":"take",
"gather":"take",
"attain":"take",
"capture":"take",
"take":"take"}

标签： pythonif-statementsimplifysimplification

解决方案

这更像是一个代码审查问题，而不是堆栈溢出问题。一个主要问题是您将类似的数据保存在单独的变量中。如果你组合你的变量，那么你可以迭代它们。

missing_parts_of_speech = ["predicate", [...]]
dict_look_up = {"predicate":predicateDict,
           [...]           
        }    
found_parts_of_speech = {}    
for word in text:
    for part in missing_parts_of_speech:
        if word in dict_look_up[part]:
            found_parts_of_speech[part] = dict_look_up[part][word]
            missing_parts_of_speech.remove(part)
            continue

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