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python - 正则表达式在几种情况下匹配版权声明中的公司名称

问题描述

我的时间很紧，要提出一个 python 正则表达式来匹配许多可能不同的版权声明中的公司名称，例如：

Copyright © 2019 Apple Inc. All rights reserved.  
© 2019 Quid, Inc. All Rights Reserved.  
© 2009 Database Designs  
© 2019 Rediker Software, All Rights Reserved  
©2019 EVOSUS, INC. ALL RIGHTS RESERVED  
© 2019 Walmart. All Rights Reserved.  
© Copyright 2003-2019 Exxon Mobil Corporation. All Rights Reserved.  
Copyright © 1978-2019 Berkshire Hathaway Inc.  
© 2019 McKesson Corporation  
© 2019 UnitedHealth Group. All rights reserved.  
© Copyright 1999 - 2019 CVS Health  
Copyright 2019 General Motors. All Rights Reserved.  
© 2019 Ford Motor Company  
©2019 AT&T Intellectual Property. All rights reserved.  
© 2019 GENERAL ELECTRIC  
Copyright ©2019 AmerisourceBergen Corporation. All Rights Reserved.  
© 2019 Verizon  
© 2019 Fannie Mae  
Copyright © 2018 Jonas Construction Software Inc. All rights reserved.  
All Comments © Copyright 2017 Kroger | The Kroger Co. All Rights Reserved  
© 2019 Express Scripts Holding Company. All Rights Reserved. 1 Express Way, St. Louis, MO 63121  
© 2019 JPMorgan Chase & Co.  
Copyright © 1995 - 2018 Boeing. All Rights Reserved.  
© 2019 Bank of America Corporation. All rights reserved.  
© 1999 - 2019 Wells Fargo. All rights reserved. NMLSR ID 399801  
©2019 Cardinal Health. All rights reserved.

我所知道的正则表达式只是非常基本的东西，目前还不足以快速提出一个好的解决方案。

在我看来，至少对于这些示例，正确捕获公司名称的要求如下：

If there's a '©' or 'Copyright' in the sentence:
    After '©' or 'Copyright' - look for a year, e.g. '2019', or a year range, e.g. '1995 - 2018' or '2003-2019' (spaces are to catch as well]):
        If there's a dot somewhere after this year/year range, capture  the text until the dot. E.g. in 'Copyright © 1978-2019 Berkshire Hathaway Inc.' capture 'Berkshire Hathaway Inc'
        If there's no dot but there's the sentence 'All rights reserved', capture from the year/year range until there and also ignore any possible non-alphanumeric characters that precede it, such as spaces and commas. E.g. from '© 2019 Rediker Software, All Rights Reserved' capture 'Rediker Software'
        If there's no dot nor the sentence 'All rights reserved', capture from the year/year range until the end. E.g. from '© 2019 Verizon' Capture 'Verizon'

关于这个好的正则表达式有什么建议吗？

标签： pythonregexparsing

解决方案

您可以考虑使用正则表达式

(?i)(?:©(?:\s*Copyright)?|Copyright(?:\s*©)?)\s*\d+(?:\s*-\s*\d+)?\s*(.*?(?=\W*All\s+rights\s+reserved)|[^.]*(?=\.)|.*)

请参阅正则表达式演示。使用不区分大小写的修饰符re.I。

细节

  • (?:©(?:\s*Copyright)?|Copyright(?:\s*©)?)- 任何一个
    • ©(?:\s*Copyright)?- ©char 后跟 0+ 个空格的可选子字符串，然后Copyright
    • |- 或者
    • Copyright(?:\s*©)?-Copyright后跟 0+ 个空格和©字符的可选子字符串
  • \s*- 0+ 个空格
  • \d+- 1+ 位（\d{4}如果年份总是包含 4 位，则使用）
  • (?:\s*-\s*\d+)?- 一个可选序列，-包含 0+ 个空格，然后是 1+ 个数字（\d{4}如果年份总是包含 4 个数字，则使用）
  • \s*- 0+ 个空格
  • (.*?(?=\W*All\s+rights\s+reserved)|[^.]*(?=\.)|.*)-捕获组 1：任何替代方案：
    • .*?(?=\W*All\s+rights\s+reserved)- 除换行符以外的任何 0+ 个字符，尽可能少，最多 0+ 个非单词字符后跟All rights reserved字符串
    • [^.]*(?=\.).- 除了尽可能多的字符之外的任何 0+ 字符，但.不包括.
    • .*- 线路的其余部分

Python演示：

import re
s = "Copyright © 2019 Apple Inc. All rights reserved.\r\n© 2019 Quid, Inc. All Rights Reserved.\r\n© 2009 Database Designs \r\n© 2019 Rediker Software, All Rights Reserved\r\n©2019 EVOSUS, INC. ALL RIGHTS RESERVED\r\n© 2019 Walmart. All Rights Reserved.\r\n© Copyright 2003-2019 Exxon Mobil Corporation. All Rights Reserved.\r\nCopyright © 1978-2019 Berkshire Hathaway Inc.\r\n© 2019 McKesson Corporation\r\n© 2019 UnitedHealth Group. All rights reserved.\r\n© Copyright 1999 - 2019 CVS Health\r\nCopyright 2019 General Motors. All Rights Reserved.\r\n© 2019 Ford Motor Company\r\n©2019 AT&T Intellectual Property. All rights reserved.\r\n© 2019 GENERAL ELECTRIC\r\nCopyright ©2019 AmerisourceBergen Corporation. All Rights Reserved.\r\n© 2019 Verizon\r\n© 2019 Fannie Mae\r\nCopyright © 2018 Jonas Construction Software Inc. All rights reserved.\r\nAll Comments © Copyright 2017 Kroger | The Kroger Co. All Rights Reserved\r\n© 2019 Express Scripts Holding Company. All Rights Reserved. 1 Express Way, St. Louis, MO 63121\r\n© 2019 JPMorgan Chase & Co.\r\nCopyright © 1995 - 2018 Boeing. All Rights Reserved.\r\n© 2019 Bank of America Corporation. All rights reserved.\r\n© 1999 - 2019 Wells Fargo. All rights reserved. NMLSR ID 399801\r\n©2019 Cardinal Health. All rights reserved.\r\n© 2019 Quid, Inc All Rights Reserved."
rx = r"(?:©(?:\s*Copyright)?|Copyright(?:\s*©)?)\s*\d+(?:\s*-\s*\d+)?\s*(.*?(?=\W*All\s+rights\s+reserved)|[^.\n]*(?=\.)|.*)"
for m in re.findall(rx, s, re.I):
    print(m)

输出：

Apple Inc
Quid, Inc
Database Designs 
Rediker Software
EVOSUS, INC
Walmart
Exxon Mobil Corporation
Berkshire Hathaway Inc
McKesson Corporation
UnitedHealth Group
CVS Health
General Motors
Ford Motor Company
AT&T Intellectual Property
GENERAL ELECTRIC
AmerisourceBergen Corporation
Verizon
Fannie Mae
Jonas Construction Software Inc
Kroger | The Kroger Co
Express Scripts Holding Company
JPMorgan Chase & Co
Boeing
Bank of America Corporation
Wells Fargo
Cardinal Health
Quid, Inc

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